Mar 27 03:00 PM PDT  04:00 PM PDT Join a free live webinar and learn the winning strategy for a 700+ score on GMAT & the perfect application. Save your spot today! Wednesday, March 27th at 3 pm PST Mar 29 10:00 PM PDT  11:00 PM PDT Right now, their GMAT prep, GRE prep, and MBA admissions consulting services are up to $1,100 off. GMAT (Save up to $261): SPRINGEXTRAGMAT GRE Prep (Save up to $149): SPRINGEXTRAGRE MBA (Save up to $1,240): SPRINGEXTRAMBA Mar 30 07:00 AM PDT  09:00 AM PDT Attend this webinar and master GMAT SC in 10 days by learning how meaning and logic can help you tackle 700+ level SC questions with ease. Mar 31 07:00 AM PDT  09:00 AM PDT Attend this webinar to learn a structured approach to solve 700+ Number Properties question in less than 2 minutes.
Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 23 Jun 2009
Posts: 178
Location: Brazil
GMAT 1: 470 Q30 V20 GMAT 2: 620 Q42 V33

For the 5 days shown in the graph, how many kilowatthours greater was
[#permalink]
Show Tags
13 Jan 2017, 10:50
Question Stats:
80% (01:19) correct 20% (01:20) wrong based on 183 sessions
HideShow timer Statistics
For the 5 days shown in the graph, how many kilowatthours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use? A) 1 B) 2 C) 3 D) 4 E) 5
Official Answer and Stats are available only to registered users. Register/ Login.
Attachments
daily.JPG [ 17.29 KiB  Viewed 4927 times ]



Director
Joined: 05 Mar 2015
Posts: 999

Re: For the 5 days shown in the graph, how many kilowatthours greater was
[#permalink]
Show Tags
13 Jan 2017, 20:23
felippemed wrote: For the 5 days shown in the graph, how many kilowatthours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?
A) 1 B) 2 C) 3 D) 4 E) 5 well the median is =27 from set (19,24,27,29,31) and mean is (31+29+27+24+19)/5 =26 thus difference =2726 =1 Ans A



Board of Directors
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4404
Location: India
GPA: 3.5
WE: Business Development (Commercial Banking)

Re: For the 5 days shown in the graph, how many kilowatthours greater was
[#permalink]
Show Tags
14 Jan 2017, 00:20
felippemed wrote: For the 5 days shown in the graph, how many kilowatthours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?
A) 1 B) 2 C) 3 D) 4 E) 5 Median Data \(= { 19 , 24 , 27 , 29 , 31 }\) & \(Median = 27\) Mean= \(\frac{( 31 + 27 + 29 + 24 + 19 )}{5} = 26\) Difference between Median and Mean = 27  26 => 1 Hence, answer will be (A) 1
_________________



Current Student
Joined: 17 Jun 2016
Posts: 502
Location: India
GMAT 1: 720 Q49 V39 GMAT 2: 710 Q50 V37
GPA: 3.65
WE: Engineering (Energy and Utilities)

Re: For the 5 days shown in the graph, how many kilowatthours greater was
[#permalink]
Show Tags
08 May 2017, 02:07
Median of 19, 24, 27, 29 and 31 is 27 (middle value in the list) Mean = (19+24+27+29+31) / 5 = 130/5 = 26 Difference = 2726 = 1
_________________



Senior Manager
Joined: 07 Jul 2012
Posts: 376
Location: India
Concentration: Finance, Accounting
GPA: 3.5

Re: For the 5 days shown in the graph, how many kilowatthours greater was
[#permalink]
Show Tags
09 May 2017, 00:07
To find the Median, first of all arrange the data in ascending or descending order (19,24,27,29,31) Median value is the middle value of the series Median = 27 Mean= \(\frac{(19+24+27+29+31)}{5}\)= 26 Difference between Median and Mean = 27  26= 1 Answer: A. Kudos please if you like my explanation!
_________________
Kindly hit kudos if my post helps!



Study Buddy Forum Moderator
Joined: 04 Sep 2016
Posts: 1305
Location: India
WE: Engineering (Other)

For the 5 days shown in the graph, how many kilowatthours greater was
[#permalink]
Show Tags
30 Sep 2017, 10:12
Abhishek009 VeritasPrepKarishma Bunuel Engr2012 Quote: Mean= \(\frac{( 31 + 27 + 29 + 24 + 19 )}{5} = 26\) There is no shortcut to this? for eg: for AP, ,mean = \(\frac{(first term + last term)}{2}\)



Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 5409
Location: United States (CA)

Re: For the 5 days shown in the graph, how many kilowatthours greater was
[#permalink]
Show Tags
08 Mar 2019, 08:06
felippemed wrote: For the 5 days shown in the graph, how many kilowatthours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?
A) 1 B) 2 C) 3 D) 4 E) 5 Listing the numbers from smallest to largest, we have: 19, 24, 27, 29 and 31. So 27 is the median. The average is (19 + 24 + 27 + 29 + 31)/5 = 130/5 = 26. Therefore, the median exceeds the average by 1. Answer: A
_________________
5star rated online GMAT quant self study course See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews




Re: For the 5 days shown in the graph, how many kilowatthours greater was
[#permalink]
08 Mar 2019, 08:06






