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For the 5 days shown in the graph, how many kilowatthours greater was
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13 Jan 2017, 10:50
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For the 5 days shown in the graph, how many kilowatthours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use? A) 1 B) 2 C) 3 D) 4 E) 5 Attachment:
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Re: For the 5 days shown in the graph, how many kilowatthours greater was
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13 Jan 2017, 20:23
felippemed wrote: For the 5 days shown in the graph, how many kilowatthours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?
A) 1 B) 2 C) 3 D) 4 E) 5 well the median is =27 from set (19,24,27,29,31) and mean is (31+29+27+24+19)/5 =26 thus difference =2726 =1 Ans A



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Re: For the 5 days shown in the graph, how many kilowatthours greater was
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14 Jan 2017, 00:20
felippemed wrote: For the 5 days shown in the graph, how many kilowatthours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?
A) 1 B) 2 C) 3 D) 4 E) 5 Median Data \(= { 19 , 24 , 27 , 29 , 31 }\) & \(Median = 27\) Mean= \(\frac{( 31 + 27 + 29 + 24 + 19 )}{5} = 26\) Difference between Median and Mean = 27  26 => 1 Hence, answer will be (A) 1
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Re: For the 5 days shown in the graph, how many kilowatthours greater was
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08 May 2017, 02:07
Median of 19, 24, 27, 29 and 31 is 27 (middle value in the list) Mean = (19+24+27+29+31) / 5 = 130/5 = 26 Difference = 2726 = 1
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Re: For the 5 days shown in the graph, how many kilowatthours greater was
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09 May 2017, 00:07
To find the Median, first of all arrange the data in ascending or descending order (19,24,27,29,31) Median value is the middle value of the series Median = 27 Mean= \(\frac{(19+24+27+29+31)}{5}\)= 26 Difference between Median and Mean = 27  26= 1 Answer: A. Kudos please if you like my explanation!
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Re: For the 5 days shown in the graph, how many kilowatthours greater was
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30 Sep 2017, 10:12
Abhishek009 VeritasPrepKarishma Bunuel Engr2012 Quote: Mean= \(\frac{( 31 + 27 + 29 + 24 + 19 )}{5} = 26\) There is no shortcut to this? for eg: for AP, ,mean = \(\frac{(first term + last term)}{2}\)



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Re: For the 5 days shown in the graph, how many kilowatthours greater was
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08 Mar 2019, 08:06
felippemed wrote: For the 5 days shown in the graph, how many kilowatthours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?
A) 1 B) 2 C) 3 D) 4 E) 5 Listing the numbers from smallest to largest, we have: 19, 24, 27, 29 and 31. So 27 is the median. The average is (19 + 24 + 27 + 29 + 31)/5 = 130/5 = 26. Therefore, the median exceeds the average by 1. Answer: A
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Re: For the 5 days shown in the graph, how many kilowatthours greater was
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