For the 5 days shown in the graph, how many kilowatt-hours greater was

Question

https://gmatclub.com/forum/download/file.php?id=33766 For the 5 days shown in the graph, how many kilowatt-hours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use? A) 1 B) 2 C) 3 D) 4 E) 5 daily.JPG

rohit8865 · Answer

well the median is =27 from set (19,24,27,29,31)
and mean is (31+29+27+24+19)/5 =26
thus difference =27-26 =1
Ans A

Abhishek009 · Answer

Median Data  = { 19 , 24 , 27 , 29 , 31 }  &  Median = 27

Mean=  \frac{( 31 + 27 + 29 + 24 + 19 )}{5} = 26

Difference between Median and Mean = 27 - 26 => 1
  
Hence, answer will be (A) 1

mihir0710 · Answer

Median of 19, 24, 27, 29 and 31 is 27 (middle value in the list)

Mean = (19+24+27+29+31) / 5 = 130/5 = 26

Difference = 27-26 = 1

varun4s · Answer

To find the Median, first of all arrange the data in ascending or descending order

(19,24,27,29,31) Median value is the middle value of the series

Median = 27

Mean=  \frac{(19+24+27+29+31)}{5} = 26

Difference between Median and Mean = 27 - 26= 1

Answer: A.

Kudos please if you like my explanation!

adkikani · Answer

Abhishek009   VeritasPrepKarishma   Bunuel   Engr2012

There is no shortcut to this? for eg: for AP, ,mean =  \frac{(first term + last term)}{2}

ScottTargetTestPrep · Answer

Listing the numbers from smallest to largest, we have: 19, 24, 27, 29 and 31. So 27 is the median. The average is (19 + 24 + 27 + 29 + 31)/5 = 130/5 = 26. Therefore, the median exceeds the average by 1.

Answer: A

sraki · Answer

This is what I did, not sure if its faster:

27-(27+((-4+-2+0+3+8)/5)) = (-6+11)/5 = 1

The median is 27, and I took the base as 27.

To get the mean , you can find the average of the differences of each of the other terms from the base to the base.

For the 5 days shown in the graph, how many kilowatt-hours greater was

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For the 5 days shown in the graph, how many kilowatt-hours greater was

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