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# For the nonzero numbers a, b, and c, define D(a,b,c) = abc/(a+b+c)

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Math Expert
Joined: 02 Sep 2009
Posts: 59725
For the nonzero numbers a, b, and c, define D(a,b,c) = abc/(a+b+c)  [#permalink]

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18 Mar 2019, 23:57
00:00

Difficulty:

5% (low)

Question Stats:

100% (00:29) correct 0% (00:00) wrong based on 26 sessions

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For the nonzero numbers a, b, and c, define $$D(a,b,c)=\frac{abc}{a+b+c}$$. Find D(2,4,6).

(A) 1
(B) 2
(C) 4
(D) 6
(E) 24

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Joined: 25 Dec 2018
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Schools: ISB '20
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Re: For the nonzero numbers a, b, and c, define D(a,b,c) = abc/(a+b+c)  [#permalink]

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19 Mar 2019, 03:02
1
Given,
D(a,b,c)=abc/a+b+c
D(2,4,6)= 2*4*6/(2+4+6)
=4
Re: For the nonzero numbers a, b, and c, define D(a,b,c) = abc/(a+b+c)   [#permalink] 19 Mar 2019, 03:02
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# For the nonzero numbers a, b, and c, define D(a,b,c) = abc/(a+b+c)

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