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For the sequence above, in which any term n is defined as 3n + 4, what

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For the sequence above, in which any term n is defined as 3n + 4, what  [#permalink]

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New post 20 Mar 2016, 23:50
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Re: For the sequence above, in which any term n is defined as 3n + 4, what  [#permalink]

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New post 21 Mar 2016, 03:52
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Bunuel wrote:
S1 = 7
S2 = 10
...
Sn = 3n + 4

For the sequence above, in which any term n is defined as 3n + 4, what is the value of n for the first term in the sequence to exceed 50?

A. 15
B. 16
C. 17
D. 18
E. 19



Nth term is 3n+4..
so 3n+4>50..
3n>46..
\(3n>\frac{46}{3}\)..
\(n>15 \frac{1}{3}\)..
so n=16
B
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Re: For the sequence above, in which any term n is defined as 3n + 4, what  [#permalink]

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New post 07 Aug 2016, 13:41
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Bunuel wrote:
S1 = 7
S2 = 10
...
Sn = 3n + 4

For the sequence above, in which any term n is defined as 3n + 4, what is the value of n for the first term in the sequence to exceed 50?

A. 15
B. 16
C. 17
D. 18
E. 19


chetan2u's solution is perfect. However, if you didn't see that approach, you can always TEST THE ANSWER CHOICES

Answer choice A: 15
term15 = 3(15) + 4 = 49
No good.

Answer choice B: 16
term16 = 3(16) + 4 = 52

Perfect!

Answer:

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Re: For the sequence above, in which any term n is defined as 3n + 4, what  [#permalink]

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New post 29 Jun 2017, 19:32
For the value to exceed 50, 3n should be 46 or greater. The first multiple of 3 that is more than 46 is 48, i.e the number in question is \(\frac{48}{3}\)=16
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Re: For the sequence above, in which any term n is defined as 3n + 4, what  [#permalink]

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New post 29 Jun 2017, 22:45
3n+4 = 50
3n = 46
n = 15.33

So, for n = 16, the value should be more than 50. Ans - B.
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Re: For the sequence above, in which any term n is defined as 3n + 4, what   [#permalink] 29 Jun 2017, 22:45
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