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Formulae for 3 overlapping sets

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Re: Formulae for 3 overlapping sets  [#permalink]

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New post 10 Jul 2016, 04:13
In a village of 100 households, 75 have at least one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x – y is:

A. 65

B. 55

C. 45

D. 35

E. 25

I did understand that X would be 55 but did not understand how y / minima is calculated. Can anyone please explain this again? It isn't clear
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Re: Formulae for 3 overlapping sets  [#permalink]

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New post 10 Jul 2016, 05:21
kamkaul wrote:
In a village of 100 households, 75 have at least one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x – y is:

A. 65

B. 55

C. 45

D. 35

E. 25

I did understand that X would be 55 but did not understand how y / minima is calculated. Can anyone please explain this again? It isn't clear


You can find several different solutions of this problem here: in-a-village-of-100-households-75-have-at-least-one-dvd-98257.html
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Re: Formulae for 3 overlapping sets  [#permalink]

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Re: Formulae for 3 overlapping sets   [#permalink] 15 Mar 2019, 02:50
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