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The trick is to realize that the only possible arrangement can be MBMBMBM and not the BMBMBMM because boys are fewer than men
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wishmasterdj
The trick is to realize that the only possible arrangement can be MBMBMBM and not the BMBMBMM because boys are fewer than men
but it can be MMBMBMB also ? so i got preferred ways 3*3!*4!
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sequiipsum

but it can be MMBMBMB also ? so i got preferred ways 3*3!*4!

MMBMBMB is not an alternating arrangement because the first two positions are both men.

Since there are 4 men and 3 boys, the only possible alternating pattern is:

MBMBMBM

So the favorable arrangements come only from this pattern.
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total = 7
men= 4
boy= 3

condition = men and boy occupy alternate position.

in this case 1st and last need to be men.

MBMBMBM

total arrangement = 7!
for men =4!
for boy =3!

4!3! /7!

1/35

option D
Bunuel
Four men and three boys are arranged in a straight line. What is the probability that the men and the boys occupy alternate position?

A. 1/7
B. 1/20
C. 1/30
D. 1/35
E. 1/70
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