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Geometry - similar triangles (easy)

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Intern
Joined: 31 Aug 2016
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Geometry - similar triangles (easy) [#permalink]

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26 Nov 2017, 06:57
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We are looking for the length of CD. The triangles ACD and BAD are similar because they both have a right angle and they share the angle D?

Thanks!
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Math Expert
Joined: 02 Aug 2009
Posts: 5356

Kudos [?]: 6144 [0], given: 121

Re: Geometry - similar triangles (easy) [#permalink]

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26 Nov 2017, 07:12
standyonda wrote:
We are looking for the length of CD. The triangles ACD and BAD are similar because they both have a right angle and they share the angle D?

Thanks!

The question becomes easier if you know : PERPENDICULAR/Altitude from hypotenuse divides the right triangle in two right triangles that are similar to each other as well as to the original triangle.

so $$\frac{CD}{AC} = \frac{AC}{BC} ........ \frac{CD}{4}=\frac{4}{3}....CD = \frac{16}{3}$$

the Q is discussed here otherwise
https://gmatclub.com/forum/in-triangle-abc-to-the-right-if-bc-3-and-ac-4-then-88061.html
_________________

Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

Kudos [?]: 6144 [0], given: 121

Math Expert
Joined: 02 Sep 2009
Posts: 42630

Kudos [?]: 135804 [0], given: 12714

Re: Geometry - similar triangles (easy) [#permalink]

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26 Nov 2017, 07:44
standyonda wrote:
We are looking for the length of CD. The triangles ACD and BAD are similar because they both have a right angle and they share the angle D?

Thanks!

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Kudos [?]: 135804 [0], given: 12714

Re: Geometry - similar triangles (easy)   [#permalink] 26 Nov 2017, 07:44
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