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George tried to compute the mean average of his 8 test scores. He mistakenly divided the correct sum of all of his test scores by 7 and got an average of 96. What is George’s actual mean test score?
(A) 80
(B) 84
(C) 96
(D) 100
(E) 108
(A) 80
(B) 84
(C) 96
(D) 100
(E) 108
24 May 2017, 05:38
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George tried to compute the mean average of his 8 test scores. He mistakenly divided the correct sum of all of his test scores by 7 and got an average of 96. What is George’s actual mean test score?
(A) 80
(B) 84
(C) 96
(D) 100
(E) 108
(A) 80
(B) 84
(C) 96
(D) 100
(E) 108
Let T = the sum of all of George's test scores.
George divided the sum of his test scores by 7 to get 96.
So we get: T/7 = 96
Multiply both sides by 7 to get: T = (96)(7)
To get the ACTUAL average, George SHOULD have divided the sum of his test scores by 8
So, ACTUAL average = T/8
= (96)(7)/8
= (12)(7)
= 84
Answer:
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