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15 Aug 2009, 14:52
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
67% (02:00) correct
33%
(01:53)
wrong
based on 15
sessions
History
Date
Time
Result
Not Attempted Yet
Given that a>1 and b>1. Is (a^x)(b^y)<1?
(1) a^(x+y) < 1
(2) b^(x+y) < 1
(1) a^(x+y) < 1
(2) b^(x+y) < 1
Archived Topic
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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15 Aug 2009, 23:58
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yezz
St1:
Given: a^(x+y) < 1 => a^x * a^y < 1
St1 could be true in the following 3 cases:
a) x<=0 & y<=0 .............. (They cannot be both zero at the same time)
-> (a^x)(b^y)<1 is TRUE
b) x<0, y>=0 & y < Abs(x), where Abs(x) means absolute value of x
-> Whether (a^x)(b^y)<1 is true or not depends on the relation between a & b.
c) y<0, x>=0 & x < Abs(y), where Abs(y) means absolute value of y
-> Whether (a^x)(b^y)<1 is true or not depends on the relation between a & b.
=> NOT SUFFICIENT
St2:
By same reasoning,
=> NOT SUFFICIENT
St1 & St2 Together:
Since we still donot know and cannot deduce any relation between a & b, we cannot conclude anything.
=> NOT SUFFICIENT
ANS: E
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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