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Given the two equations 3r + s = 17 and r + 2s = 9, by how much does

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Joined: 02 Sep 2009
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Kudos [?]: 135354 [0], given: 12690

Given the two equations 3r + s = 17 and r + 2s = 9, by how much does [#permalink]

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New post 07 Feb 2016, 10:04
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

87% (01:11) correct 13% (01:02) wrong based on 61 sessions

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Kudos [?]: 135354 [0], given: 12690

Manager
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Joined: 18 Aug 2013
Posts: 150

Kudos [?]: 58 [0], given: 127

Location: India
Concentration: Operations, Entrepreneurship
GMAT 1: 640 Q48 V28
GPA: 3.92
WE: Operations (Transportation)
Re: Given the two equations 3r + s = 17 and r + 2s = 9, by how much does [#permalink]

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New post 13 Feb 2016, 09:56
Solve by Simultaneous Equations.

My Answer is A.

r=5
s=2

Kudos [?]: 58 [0], given: 127

Intern
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Joined: 24 Jul 2017
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Kudos [?]: 0 [0], given: 285

Re: Given the two equations 3r + s = 17 and r + 2s = 9, by how much does [#permalink]

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New post 26 Sep 2017, 02:42
Bunuel wrote:
Given the two equations 3r + s = 17 and r + 2s = 9, by how much does r exceed s?

A. 3
B. 4
C. 5
D. 6
E. 7


solve for these 2 eqns , you ll get r =5 & s =2
hence r-s = 5-2 = 3

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Expert Post
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Status: Head GMAT Instructor
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Joined: 04 Mar 2011
Posts: 1793

Kudos [?]: 980 [0], given: 5

Re: Given the two equations 3r + s = 17 and r + 2s = 9, by how much does [#permalink]

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New post 29 Sep 2017, 10:32
Bunuel wrote:
Given the two equations 3r + s = 17 and r + 2s = 9, by how much does r exceed s?

A. 3
B. 4
C. 5
D. 6
E. 7


We can multiply the second equation by -3 and we have:

-3r - 6s = -27

When we add this equation to the first equation, the terms containing r cancel out, and we now have:

-5s = -10

s = 2

Thus:

r + 2(2) = 9

r = 5

So, r is 3 greater than s.

Answer: A
_________________

Jeffery Miller
Head of GMAT Instruction

GMAT Quant Self-Study Course
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Kudos [?]: 980 [0], given: 5

Re: Given the two equations 3r + s = 17 and r + 2s = 9, by how much does   [#permalink] 29 Sep 2017, 10:32
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