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Re: GMAT Club test M25: # 31 [#permalink]
srini123 wrote:
3^3=27

and 3^3^3 = 3^27

where is the doubt ?


srini123
I can understand if the question is: 3^(3^3). In this case we have to solve the bracket first. But the question does not say that. So according to basic rules of exponents, it should be 3^(3*3) = 3^9 and not 3^27.
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Re: GMAT Club test M25: # 31 [#permalink]
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hgp2k wrote:
srini123 wrote:
3^3=27

and 3^3^3 = 3^27

where is the doubt ?


srini123
I can understand if the question is: 3^(3^3). In this case we have to solve the bracket first. But the question does not say that. So according to basic rules of exponents, it should be 3^(3*3) = 3^9 and not 3^27.
- also I didn't quite get where did the * come from ? I see now, \(((3^3)^3 = 3^9)\), but for the one in question we need to apply precedence of operators (see below)

As per precedence of power, 3^3^3 = 3^(3^3)

see https://en.wikipedia.org/wiki/Order_of_operations
specifically, example
2. Evaluate exponential powers; for iterated powers, start from the right:

2^{3^2}=2^{[3^2]}=[2^9]=512
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Re: GMAT Club test M25: # 31 [#permalink]
okay, I got it now. Thanks Srini +1 for quick answer and all your help :)
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Re: GMAT Club test M25: # 31 [#permalink]
This question has already been discussed:
gmat-test-m25-master-thread-all-discussions-78460.html

Please don't create double posts on the same questions. You can search this thread:
gmat-club-tests-master-threads-all-tests-78599.html

Also, don't forget to use forum search and Custom Google Search for the same purpose.

Thank you :).
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Re: GMAT Club test M25: # 31 [#permalink]
Thanks dzyubam! I will take care of it going further.

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