How many integers between 324,700 and 458,600 have a 2 in the tens digit and a 1 in the units digit?

I solved in the following manner:

The number are from 324700 to 458600. That is from 324700 to 399999 and from 400000 to 458600.

The number of numbers ending in 21 from 324700 to 399999:

1*8*6*3*1*1=144 total (i.e. only the three digits will change. First digit and the last two digits are constant)

The number of numbers ending in 21 from 400000 to 458600:

1*6*9*7*1*1=378

so total= 144+378=522 but answer is 1339.

Please Bunuel let me know where I am committing the mistake.

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