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07 Jun 2009, 14:25
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Could someone please help with this?
Thanks!
Thanks!
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07 Jun 2009, 14:55
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Please state the source. Also, your subject is very vague. Considering you have posted bunches of questions with the same subject line, you're not likely to get many responses.
07 Jun 2009, 15:48
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Here's one where it pays to analyze the question stem a little bit before proceeding.
The question asks for the average of \(3x\) and \(6y\), two things, and so to find the average you divide that sum by 2. \((3x+6y) / 2\) can simplify to \(x+2y\). Now it becomes clear that statement 1 suffices.
It shouldn't be too difficult to see why Statement 2 is insufficient. To really nail home that it isn't, one could use examples, though that shouldn't reeeeeally be necessary. Suppose \(x\) is 4 and \(y\) is 2. That satisfies the statement, and then the average in question is 8. However, it could also be the case that, for example, \(x\) is 1 and \(y\) is 5. In this case, the average in question is 11. Whatever. (And when I say "average", i'm really just plugging into \(x+2y\)). Since we get different answers, it's insufficient.
The question asks for the average of \(3x\) and \(6y\), two things, and so to find the average you divide that sum by 2. \((3x+6y) / 2\) can simplify to \(x+2y\). Now it becomes clear that statement 1 suffices.
It shouldn't be too difficult to see why Statement 2 is insufficient. To really nail home that it isn't, one could use examples, though that shouldn't reeeeeally be necessary. Suppose \(x\) is 4 and \(y\) is 2. That satisfies the statement, and then the average in question is 8. However, it could also be the case that, for example, \(x\) is 1 and \(y\) is 5. In this case, the average in question is 11. Whatever. (And when I say "average", i'm really just plugging into \(x+2y\)). Since we get different answers, it's insufficient.
