Is the mean of Set A equal to mean of Set B?

Question

GMATBusters’ Quant Quiz Question -2 
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Is the mean of Set A equal to mean of Set B?
A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.

1) Range of set A is greater than the range of set B.
2) Sum of all numbers in set A < Sum of all the numbers in set B

GMATBusters · Answer

The Official Solution is as follows https://gmatclub.com/forum/download/file.php?id=52758 WhatsApp Image 2020-02-03 at 6.49.55 PM (1).jpeg

akadiyan · Answer

Is the mean of Set A equal to mean of Set B?
A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.

Given:
1.Set A Consists of 7 different numbers - There is no specific information about whether they have 0 or negative numbers.
2.Set B consists of 6 positive numbers and all elements of Set B are part of Set A

1) Range of set A is greater than the range of set B.

Consider two different sets given below
Set A with first 7 numbers as elements and Set 6 with either from 2 to 7 or 1 to 6. When set B consists of 1 {1,2,3,4,5,6} , the mean is 3.5 and when set B consists of {2,3,4,5,6,7}, the mean is 4.5. In both the case the mean is not equal.

Consider having 0 in set A, in this case the range will be higher and the mean will remain same.
If A has a negative number, then range of A will be higher but the mean will vary.

Option A is not sufficient.

2) Sum of all numbers in set A < Sum of all the numbers in set B

Since Sum of all numbers is same and all of elements of Set B is in set A, the only number that could be in set A in this case is 0.

If we add only 0 to A, then mean of set A will be smaller than mean of set B.

Option B is sufficient.

Ans: B

AndreV · Answer

1) Let's say that A=B U {x}. There's no constraint for x other than being different from all numbers in the set, so x can either be negative or positive or zero. Let's suppose that Sb is the sum of all terms in set B. Then if we wanted the means to be equal, we'd need to find an x that:
(Sb+x)/7=Sb/6
here x= Sb/6 >0
As we can seen the term to be added for the means to be equal is equal to the mean of set B, which is clearly greater than the lowest member in B. Therefore, there is no x than satisfy both the question and the first statement.
Clearly this statement is sufficient.
2) sum of all numbers in set A <sum of all numbers in set B. If we divide each term by 7, we have
(sum of all numbers in set A)/7 <(sum of all numbers in set B)/7
But (sum of all numbers in set B)/7 <(sum of all numbers in set B)/6  . Then,
(sum of all numbers in set A)/7 <(sum of all numbers in set B)/6
mean(A)<mean(B)
Clearly this statement is sufficient.
Answer: D

ITGMAT · Answer

Qs : Is the mean of Set A equal to mean of Set B? 
which can be written as Mean A= Mean B? 
Given : A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.

let set A =   and set B=  
however it is not mentioned that all numbers in set A are positive. we can derive from set B that only 6 no. are positive. so the remaining number n can be positive or negative in set A. this number n will decide the total sum.

1) Range of set A is greater than the range of set B.

as we know that range = largest number - smallest number 
Range of A, RA= 7-1 = 6 if n=1
RA= 7-(-1)= 8 if n = -1
therefore mean A may or may not be greater than mean B.

Mean A=  /7=  /7 so mean of A depends on number n. 
as range of A is greater than range of set B then this "n" must be less than the smallest value of set B i.e. 2 in above case considering the largest number is same. therefore the mean of A and mean of B will not be same. hence it is possible to get unique answer. this condition is sufficient.

2) Sum of all numbers in set A < Sum of all the numbers in set B
mean = total sum/number of terms
as total number of terms is more in set A, the mean of A will be less.

/7 <  /6
mean A< mean B
hence sufficient to answer the question.

The answer is D.

dkilroy · Answer

Is the mean of Set A equal to mean of Set B?
A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.

Immediately, I can tell that the only way this would be true is if the 7th number of Set A is equal to the mean, and every other number are numbers in Set B. Ex: A{1,2,3, 4 ,5,6,7} | B{1,2,3,5,6,7} . This is true because Set A contains Set B, and each number is different.

1) Range of set A is greater than the range of set B. This means that the 7th "extra" number of Set A is either the first or last number, and so not equal to the mean of the rest of the set. Ex: A{1,2,3,5,6,7,8} | B{1,2,3,5,6,7} Sufficient (to disprove)

2) Sum of all numbers in set A < Sum of all the numbers in set B. Because Set A contains 6 positive numbers, all of which are also in set B, this means that the 7th extra number is less than 0, making sum of Set A < Set B. Ex: A{-1,1,2,3,5,6,7} B{1,2,3,5,6,7}. Sufficient (to disprove)

Answer: D

merajul · Answer

Is the mean of Set A equal to mean of Set B?
A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.

Given:
1.Set A Consists of 7 different numbers - There is no specific information about whether they have 0 or negative numbers.
2.Set B consists of 6 positive numbers and all elements of Set B are part of Set A

1) Range of set A is greater than the range of set B.

Consider two different sets given below
Set A with first 7 numbers as elements and Set 6 with either from 2 to 7 or 1 to 6. When set B consists of 1 {1,2,3,4,5,6} , the mean is 3.5 and when set B consists of {2,3,4,5,6,7}, the mean is 4.5. In both the case the mean is not equal.

Consider having 0 in set A, in this case the range will be higher and the mean will remain same.
If A has a negative number, then range of A will be higher but the mean will vary.

Option A is not sufficient.

2) Sum of all numbers in set A < Sum of all the numbers in set B

Since Sum of all numbers is same and all of elements of Set B is in set A, the only number that could be in set A in this case is 0.

If we add only 0 to A, then mean of set A will be smaller than mean of set B.

Option B is sufficient.

Ans: B

Archit3110 · Answer

#1
Range of set A is greater than the range of set B
A has larger value than B ; so the mean value of A is not same as B ; sufficient
#2
 Sum of all numbers in set A < Sum of all the numbers in set B
since sum of integers is less than set B ; so mean is not same ; sufficient
IMO D 
Is the mean of Set A equal to mean of Set B?
A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.

1) Range of set A is greater than the range of set B.
2) Sum of all numbers in set A < Sum of all the numbers in set B

J2S2019 · Answer

Answer is B.
Given attachment for explanation

bumpbot · Answer

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Is the mean of Set A equal to mean of Set B?

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