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Is the mean of Set A equal to mean of Set B?
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01 Feb 2020, 18:05
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GMATBusters’ Quant Quiz Question 2 For questions from previous quizzes click hereIs the mean of Set A equal to mean of Set B? A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A. 1) Range of set A is greater than the range of set B. 2) Sum of all numbers in set A < Sum of all the numbers in set B
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Re: Is the mean of Set A equal to mean of Set B?
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01 Feb 2020, 18:09
The Official Solution is as follows Attachment:
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Re: Is the mean of Set A equal to mean of Set B?
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01 Feb 2020, 18:29
Is the mean of Set A equal to mean of Set B? A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A. Given: 1.Set A Consists of 7 different numbers  There is no specific information about whether they have 0 or negative numbers. 2.Set B consists of 6 positive numbers and all elements of Set B are part of Set A 1) Range of set A is greater than the range of set B. Consider two different sets given below Set A with first 7 numbers as elements and Set 6 with either from 2 to 7 or 1 to 6. When set B consists of 1 {1,2,3,4,5,6} , the mean is 3.5 and when set B consists of {2,3,4,5,6,7}, the mean is 4.5. In both the case the mean is not equal. Consider having 0 in set A, in this case the range will be higher and the mean will remain same. If A has a negative number, then range of A will be higher but the mean will vary. Option A is not sufficient. 2) Sum of all numbers in set A < Sum of all the numbers in set B Since Sum of all numbers is same and all of elements of Set B is in set A, the only number that could be in set A in this case is 0. If we add only 0 to A, then mean of set A will be smaller than mean of set B. Option B is sufficient. Ans: B
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Is the mean of Set A equal to mean of Set B?
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Updated on: 03 Feb 2020, 10:27
1) Let's say that A=B U {x}. There's no constraint for x other than being different from all numbers in the set, so x can either be negative or positive or zero. Let's suppose that Sb is the sum of all terms in set B. Then if we wanted the means to be equal, we'd need to find an x that: (Sb+x)/7=Sb/6 here x= Sb/6 >0 As we can seen the term to be added for the means to be equal is equal to the mean of set B, which is clearly greater than the lowest member in B. Therefore, there is no x than satisfy both the question and the first statement. Clearly this statement is sufficient. 2) sum of all numbers in set A <sum of all numbers in set B. If we divide each term by 7, we have (sum of all numbers in set A)/7 <(sum of all numbers in set B)/7 But (sum of all numbers in set B)/7 <(sum of all numbers in set B)/6 [because the sum of all numbers in set B is positive]. Then, (sum of all numbers in set A)/7 <(sum of all numbers in set B)/6 mean(A)<mean(B) Clearly this statement is sufficient. Answer: D
Originally posted by AndreV on 01 Feb 2020, 18:50.
Last edited by AndreV on 03 Feb 2020, 10:27, edited 1 time in total.



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Re: Is the mean of Set A equal to mean of Set B?
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01 Feb 2020, 19:19
Qs : Is the mean of Set A equal to mean of Set B? which can be written as Mean A= Mean B? Given : A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.
let set A = [n, 2,3,4,5,6,7] and set B= [2,3,4,5,6,7] however it is not mentioned that all numbers in set A are positive. we can derive from set B that only 6 no. are positive. so the remaining number n can be positive or negative in set A. this number n will decide the total sum.
1) Range of set A is greater than the range of set B.
as we know that range = largest number  smallest number Range of A, RA= 71 = 6 if n=1 RA= 7(1)= 8 if n = 1 therefore mean A may or may not be greater than mean B.
Mean A= [n+ 2+3+4+5+6+7]/7= [n+ 27]/7 so mean of A depends on number n. as range of A is greater than range of set B then this "n" must be less than the smallest value of set B i.e. 2 in above case considering the largest number is same. therefore the mean of A and mean of B will not be same. hence it is possible to get unique answer. this condition is sufficient.
2) Sum of all numbers in set A < Sum of all the numbers in set B mean = total sum/number of terms as total number of terms is more in set A, the mean of A will be less.
[Sum of set A]/7 < [sum of set B]/6 mean A< mean B hence sufficient to answer the question.
The answer is D.



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Re: Is the mean of Set A equal to mean of Set B?
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01 Feb 2020, 19:37
Is the mean of Set A equal to mean of Set B? A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.
Immediately, I can tell that the only way this would be true is if the 7th number of Set A is equal to the mean, and every other number are numbers in Set B. Ex: A{1,2,3,4,5,6,7}  B{1,2,3,5,6,7} . This is true because Set A contains Set B, and each number is different.
1) Range of set A is greater than the range of set B. This means that the 7th "extra" number of Set A is either the first or last number, and so not equal to the mean of the rest of the set. Ex: A{1,2,3,5,6,7,8}  B{1,2,3,5,6,7} Sufficient (to disprove)
2) Sum of all numbers in set A < Sum of all the numbers in set B. Because Set A contains 6 positive numbers, all of which are also in set B, this means that the 7th extra number is less than 0, making sum of Set A < Set B. Ex: A{1,1,2,3,5,6,7} B{1,2,3,5,6,7}. Sufficient (to disprove)
Answer: D



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Re: Is the mean of Set A equal to mean of Set B?
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01 Feb 2020, 20:41
Is the mean of Set A equal to mean of Set B? A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A. 1) Range of set A is greater than the range of set B. 2) Sum of all numbers in set A < Sum of all the numbers in set B The question says, A is having 7 different numbers (positive or negative integer or 0 or any non integer) B is having 6 different +ve numbers, all of which is are members of A. In this question there will be 3 scenarios. Lets say, A = [1,2,3,4,5,6,X] B = [1,2,3,4,5,6] Scenario1,if X > the largest no of the set (say 7) , then [A]Mean > [B]Mean Scenario2,if X =0 then [A]Mean < [B]Mean Scenario3,if X< the smallest no of the set (say 2), then [A]Mean < [B]Mean Now, option (1) says, [A]range > [B]range. here Scenario1 & 3 shall apply. Not Sufficient Option (2) says, [A]sum < [B]sum, here Scenario 2&3 shall apply. Sufficient. Correct Answer is (B)
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Re: Is the mean of Set A equal to mean of Set B?
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02 Feb 2020, 00:34
#1 Range of set A is greater than the range of set B A has larger value than B ; so the mean value of A is not same as B ; sufficient #2 Sum of all numbers in set A < Sum of all the numbers in set B since sum of integers is less than set B ; so mean is not same ; sufficient IMO D Is the mean of Set A equal to mean of Set B? A is a set containing 7 different numbers. B is a set containing 6 different positive numbers, all of which are members of set A.
1) Range of set A is greater than the range of set B. 2) Sum of all numbers in set A < Sum of all the numbers in set B



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Re: Is the mean of Set A equal to mean of Set B?
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02 Feb 2020, 05:43
Answer is B. Given attachment for explanation
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Re: Is the mean of Set A equal to mean of Set B?
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