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Re: How many different three-digit multiples of 5 can be [#permalink]
I don't get why the combination is multiplied by two? i solved by writing out the different possibilities
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Re: How many different three-digit multiples of 5 can be [#permalink]
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legitpro wrote:
I don't get why the combination is multiplied by two? i solved by writing out the different possibilities


Available: 2, 3, 4, 5

You need to make 3 digit numbers which are multiples of 5.
___ ___ ___

For the number to be a multiple of 5, it must end with either 0 or 5. We only have 5 available so the number must end with 5.

___ ___ 5

Now you select 2 numbers out of the leftover 3 numbers (2, 3 and 4) in 3C2 ways and arrange them in the 2 places in 2! ways which gives you 3C2*2! = 6

or you can say that you can select a number for the hundreds place in 3 ways and select a number for the tens place in 2 ways (since numbers cannot be repeated). So you can make the number in 3*2 = 6 ways
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Re: How many different three-digit multiples of 5 can be [#permalink]
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beckee529 wrote:
How many distinct three-digit positive multiples of 5 can be formed from the digits 2, 3, 4, and 5 without repeating any digit?

A. 3
B. 6
C. 10
D. 12
E. 18


The units digit must be 5 for the number to be a multiple of 5: _ _ 5. This leaves us with three choices for the hundreds digit: 2, 3, or 4. Subsequently, we're left with two choices for the tens digit. Therefore, we can form 3*2 = 6 such numbers.


Answer: B
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Re: How many different three-digit multiples of 5 can be [#permalink]
Ways to arrange numbers
2,3,4 : 3!
Last digit has to be 5
3!*1
Option B


beckee529 wrote:
How many distinct three-digit positive multiples of 5 can be formed from the digits 2, 3, 4, and 5 without repeating any digit?

A. 3
B. 6
C. 10
D. 12
E. 18


Posted from my mobile device
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Re: How many different three-digit multiples of 5 can be [#permalink]
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