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Joined: 01 May 2017
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How many even numbers, larger than 400, with 3 different digits
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01 May 2017, 00:31
Question Stats:
72% (02:36) correct 28% (02:07) wrong based on 42 sessions
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How many even numbers, larger than 400, with 3 different digits, can be formed using digits 1, 2, 3, 4, 5, 6, 7, 8? A. 102 B. 620 C. 640 D. 2048 E. 2520 I am struggling to understand why 102 is the correct answer as my approach is; 5 options for the first digit, 7 for the second and from there it is already wrong because there is no integer to multiply 5*7 that result in 102. Thank you in advance P.D.: I am sorry for any possible mistake as I am new in the forum. I could not find the right topic for the problem because I have it as a counting methode. The source is from an online platform provided by my Academy.
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Re: How many even numbers, larger than 400, with 3 different digits
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01 May 2017, 01:12
alfonspm wrote: How many even numbers, larger than 400, with 3 different digits, can be formed using digits 1, 2, 3, 4, 5, 6, 7, 8?
A. 102 B. 620 C. 640 D. 2048 E. 2520
I am struggling to understand why 102 is the correct answer as my approach is; 5 options for the first digit, 7 for the second and from there it is already wrong because there is no integer to multiply 5*7 that result in 102. Thank you in advance
P.D.: I am sorry for any possible mistake as I am new in the forum. I could not find the right topic for the problem because I have it as a counting methode. The source is from an online platform provided by my Academy. 1. If the hundreds digit is even (so 4, 6, or 8):Number of options for the hundreds digit: 3; Number of options for the units digit: 3 (any from 2, 4, 6, or 8 but one used for the hundreds); Number of options for the tens digit: 6. Total = 3*3*6 = 54. 2. If the hundreds digit is odd (so 5, or 7):Number of options for the hundreds digit: 2; Number of options for the units digit: 4 (any from 2, 4, 6, or 8); Number of options for the tens digit: 6. Total = 2*4*6 = 48. GRAND TOTAL = 54 + 48 = 102. Answer: A. alfonspm wrote: P.D.: I am sorry for any possible mistake as I am new in the forum. I could not find the right topic for the problem because I have it as a counting methode. The source is from an online platform provided by my Academy.
The Category for such kind of questions in Combinations.
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Re: How many even numbers, larger than 400, with 3 different digits
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01 May 2017, 03:02
Sorry I don't understand why you split the hundreds digits into even or odds. If the number must be even the only digit you should split is the units, as are the ones that are gonna tell you whether is even or odd.



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Re: How many even numbers, larger than 400, with 3 different digits
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01 May 2017, 03:13



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How many even numbers, larger than 400, with 3 different digits
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01 May 2017, 03:17
alfonspm wrote: How many even numbers, larger than 400, with 3 different digits, can be formed using digits 1, 2, 3, 4, 5, 6, 7, 8?
A. 102 B. 620 C. 640 D. 2048 E. 2520
Sorry I don't understand why you split the hundreds digits into even or odds. If the number must be even the only digit you should split is the units, as are the ones that are gonna tell you whether is even or odd. Look at it this way Case 1: If Unit digit is taken by digit 2 then hundreds digit has 5 options and tens digit has 6 options i.e. 1*5*6 = 30 numbers Case 2: If Unit digit is taken by digit 4 or 6 or 8 then hundreds digit has 4 options and tens digit has 6 options i.e. 3*4*6 = 72 numbers Total Possibilities = 30+72 = 102 Bunuel has tried it in different ways because when hundreds digit is 4 or 6 or 8 then unit digit has 3 possibilities but when Hundreds digit is 5 or 6 then Unit digits have 4 possibilities so the cases can not be clubbed together hence they need to be solved as separate cases I hope this helps!!!
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Re: How many even numbers, larger than 400, with 3 different digits
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01 May 2017, 10:36
It does thank you very much!



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Re: How many even numbers, larger than 400, with 3 different digits
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01 May 2017, 18:06
To get # of numbers greater than 400 and even, first digit can be any number from 4 to 8 while last number should be an even number. if the last number is 2, then we have 1 way to fill the last digit; 100's place can be filled by 4,5,6,7,8(total 5) and 10th place can be filled with any number from 1 to 8, since two numbers are already being filled in last digit and 100th place, we can take only 6 digits, thus total number of numbers that end with two is 1*5*6=30 if the last number is 4,6,8, then we have 3 ways to fill the last digit; 100's place can be filled by 5,7, and any two of {4,6,8} (total 4), as the other number is filled in last digit earlier. and 10th place can be filled with any number from 1 to 8, since two numbers are already being filled in last digit and 100th place, we can take only 6 digits, thus total number of numbers that end with either [4,6,8] is 3*4*6 = 72 numbers Total number of numbers = 30+72 = 102
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Re: How many even numbers, larger than 400, with 3 different digits &nbs
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