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Bunuel
How many factors of the number \(2^9*3^6*5^5*10^4\) are multiples of 60?

A. 594
B. 648
C. 980
D. 1200
E. 2100



Are You Up For the Challenge: 700 Level Questions
\(60 = 2^2*3*5\)

\(2^9*3^6*5^5*10^4=2^{13}*3^6*5^9\)

On dividing we have -\(\frac{2^{13}*3^6*5^9}{2^2*3*5}=2^{11}*3^5*5^8\)

No of factors of the above will be \((11+1)(5+1)(8+1)=648\), Answer must be (B)
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