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How many four digit numbers have no repeat digits, do not co
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04 Nov 2013, 11:45
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How many four digit numbers have no repeat digits, do not contain zero, and have a sum of digits equal to 28? A. 14 B. 24 C. 28 D. 48 E. 96For a discussion of difficult counting questions, as well as the explanation to this question, see: http://magoosh.com/gmat/2013/difficult ... problems/Mike
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Re: How many four digit numbers have no repeat digits, do not co
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04 Nov 2013, 12:26
mikemcgarry wrote: How many four digit numbers have no repeat digits, do not contain zero, and have a sum of digits equal to 28? A. 14 B. 24 C. 28 D. 48 E. 96For a discussion of difficult counting questions, as well as the explanation to this question, see: http://magoosh.com/gmat/2013/difficult ... problems/Mike Hmm. OK, lets start with the opposite of what is not allowed. We know that it's a 4 digit no and the sum of the digits has to be 28. Also, 4*7 = 28. Let the no be 7777. However, no repetition is allowed.We try to rearrange the given digits to form other acceptable 4 digit numbers. Let's rearrange by reducing the value of the hundreds place by 1,and add it to the tens place : 7687. Again, take 2 units from the hundreds place and add it to the units place : 7489. All the conditions are met. Thus, as there are 4 distinct digits, the total no of arrangements possible: 4! = 24. Again, lets try to rearrange the given number to see if we can end up with another such unique pair of combination : Reduce the value of the thousands place by 1 and add it to the hundreds place : 6589. Again, unique combination : 4! = 24. Any other combination of value(s) will result in one of these 48 numbers. Noteworthy point: The lowest of these numbers can only be of the form : 4XYZ.
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Re: How many four digit numbers have no repeat digits, do not co
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04 Nov 2013, 13:41
First, look for all 4 digits without repeat that add up to 28. To avoid repetition, start with the highest numbers first. Start from the largest number possible 9874. Then the next largest number possible is 9865. After this, you'll realize no other solution. Clearly the solution needs to start with a 9 (cuz otherwise 8765 is the largest possible, but only equals 26). With a 9, you also need an 8 (cuz otherwise 9765 is the largest possible, but only equals 27). With 98__ only 74 and 65 work. So you have two solutions. Each can be rearranged in 4!=24 ways. So 24+24=48.
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Re: How many four digit numbers have no repeat digits, do not co
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04 Nov 2013, 14:56
farful wrote: First, look for all 4 digits without repeat that add up to 28. To avoid repetition, start with the highest numbers first.
Start from the largest number possible 9874. Then the next largest number possible is 9865.
After this, you'll realize no other solution. Clearly the solution needs to start with a 9 (cuz otherwise 8765 is the largest possible, but only equals 26). With a 9, you also need an 8 (cuz otherwise 9765 is the largest possible, but only equals 27). With 98__ only 74 and 65 work.
So you have two solutions. Each can be rearranged in 4!=24 ways. So 24+24=48. Exactly how I did it, nothing to add! Congrats
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Re: How many four digit numbers have no repeat digits, do not co
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29 Dec 2013, 18:32
mikemcgarry wrote: How many four digit numbers have no repeat digits, do not contain zero, and have a sum of digits equal to 28? A. 14 B. 24 C. 28 D. 48 E. 96For a discussion of difficult counting questions, as well as the explanation to this question, see: http://magoosh.com/gmat/2013/difficult ... problems/Mike Mike, that is an awesome question One of the best I've seen from Magoooooooosh so far Cheers! J



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How many four digit numbers have no repeat digits, do not contain zero
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13 Mar 2015, 11:25
How many four digit numbers have no repeat digits, do not contain zero, and have a sum of digits equal to 28?
A. 14
B. 24
C. 28
D. 48
E. 96



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Re: How many four digit numbers have no repeat digits, do not co
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13 Mar 2015, 11:35



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How many four digit numbers have no repeat digits, do not co
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06 Jul 2015, 09:12
checking numbers 1 x 2 x 3 x 4 ok (789) 5 ok (986) 6 ok (985) 7 ok (984) 8 ok (974) 9 ok (874) So 6 Numbers are Ok > 6! / (6!/4!2!) = 48 Could some expert please comment on this solution. It's not a standard way to solve such questions....
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How many four digit numbers have no repeat digits, do not co
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06 Jan 2016, 19:55
only 2 options work: 9+8+7+4 and 9+8+6+5
total we have 4! first arrangements + 4! second arrangements 48 in total.



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Re: How many four digit numbers have no repeat digits, do not co
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10 Jan 2016, 04:47
Let's start picking numbers from the biggest to smallest, without repetition. Pick 9,8,7  total is 24. To bring it to 28, let's pick 4. (Note that this also tells us that in any case, even with the largest numbers, we can't go below 4.) We have 9874. Now, we can reduce one of the bigger numbers (we'll have to reduce 7 as if we reduce 8 or 9, we'll repeat a digit) while simultaneously increasing the smallest number by 1. That way, we replace 4 with 5, and 7 with 6. So, the combination becomes: 9865 (sum=28). These two combinations (9874 and 9865) can lead to 4! + 4! = 48 numbers.
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Re: How many four digit numbers have no repeat digits, do not co
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10 Jan 2016, 10:44
Sum can be achieved by two combinations 9874 this can be arranged in 4! ways 9865this can be arranged in 4! ways
so 4!+4!=48



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Re: How many four digit numbers have no repeat digits, do not co
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28 Jun 2018, 12:16
mikemcgarry wrote: How many four digit numbers have no repeat digits, do not contain zero, and have a sum of digits equal to 28? A. 14 B. 24 C. 28 D. 48 E. 96For a discussion of difficult counting questions, as well as the explanation to this question, see: http://magoosh.com/gmat/2013/difficult ... problems/Mike For the sum of digits to be 28, with the given constraints, we can see only two arrangements as 9847 & 9865 The # of ways to arrange the digits in each is = 4! + 4! = 48 Answer D. Thanks, GyM
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Re: How many four digit numbers have no repeat digits, do not co
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28 Jun 2018, 15:09
First set of numbers that satisfy is 9874. Second set is 9865.
For 9874, you can have 6 variations of the #'s per starting digit. For example: 9874 9847 9784 9748 9478 9487
Each starting digit will have 6 variations each. 6*4 = 24
The same applies to 9865
24+24= 48




Re: How many four digit numbers have no repeat digits, do not co &nbs
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