Bunuel wrote:

How many four-digit numbers that do not contain the digits 3 or 6 are there?

A. 2401

B. 3584

C. 4096

D. 5040

E. 7200

1st Digit can be filled up by the numbers - { 1 , 2 , 4 , 5 , 7 , 8 , 9 } = 7 ways

2nd Digit can be filled up by the numbers - { 0, 1 , 2 , 4 , 5 , 7 , 8 , 9 } = 8 ways

3rd Digit can be filled up by the numbers - { 0, 1 , 2 , 4 , 5 , 7 , 8 , 9 } = 8 ways

So, total No of ways is 7 * 8 * 8 => 3584

Hence answer will be (B)
_________________

Thanks and Regards

Abhishek....

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