How many four-digit positive integers are there such that the four dig

Question

How many four-digit positive integers are there such that the four digits are 2, 3, 6, and 9 (without repetition)?

A. 10

B. 20

C. 24

D. 256

E. 324

yashikaaggarwal · Answer

four-digit positive integers are there such that the four digits are 2, 3, 6, and 9 (without repetition)
=> thousandth digit can be written in 4 different ways
=> hundredth digit can be written in 3 different ways
=> tenth digit can be written in 2 different ways
=> ones digit can be written in 1 way only.

=> The total no. of way = 4! => 4*3*2*1 = 24

Answer is C

Sr1994 · Answer

Let's give 4 slots

_ _ _ _

1st slot can be filled in 4 ways
2nd slot can be filled in 3 ways
3rd slot can be filled in 2 ways
4th slot can be filled in 1 way

Therefore, no:of ways = 4*3*2*1 = 24

Answer C

CrackverbalGMAT · Answer

The digits given are distinct and we have to form 4 digit numbers (i.e using all the digits0

One of the rules of permutations states that:

The number of arrangements of n distinct things/people, all taken together = n!

Here n = 4, and therefore the number of arrangements = 4! = 24

Option C

Arun Kumar

ScottTargetTestPrep · Answer

Solution:

Since there is no digit 0, any of the 4 given digits can be the first digit. In the other words, there are 4 choices for the thousands digit. Since no digits can be repeated, there are 3, 2, and 1 choices for the hundreds, tens and ones digits, respectively. Therefore, there are 4 x 3 x 2 x 1 = 24 possible integers.

Answer: C

How many four-digit positive integers are there such that the four dig

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How many four-digit positive integers are there such that the four dig

Prep Toolkit

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