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# How many hours will it take 6 identical machines, working at their con

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Math Expert
Joined: 02 Sep 2009
Posts: 58371
How many hours will it take 6 identical machines, working at their con  [#permalink]

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02 Apr 2018, 22:03
00:00

Difficulty:

15% (low)

Question Stats:

79% (01:04) correct 21% (01:04) wrong based on 83 sessions

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How many hours will it take 6 identical machines, working at their constant rates, to produce 1,200 components?

(1) Each machine produces 200 components.
(2) Two such machines, working at their constant rates, can produce 1,200 components in 9/2 hours.

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Joined: 28 Apr 2014
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GMAT 1: 640 Q50 V25
Re: How many hours will it take 6 identical machines, working at their con  [#permalink]

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02 Apr 2018, 22:08
IMO B

St 2: 2/t=2/9
T=9hrs
6/9=1/t
t=1.5hrs
Since work ie 1200 components is same, I didn't consider 1200 anywhere
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Re: How many hours will it take 6 identical machines, working at their con  [#permalink]

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03 Apr 2018, 01:07
Bunuel wrote:
How many hours will it take 6 identical machines, working at their constant rates, to produce 1,200 components?

(1) Each machine produces 200 components.
(2) Two such machines, working at their constant rates, can produce 1,200 components in 9/2 hours.

Question: How many hours will it take 6 identical machines, working at their constant rates, to produce 1,200 components?

CONCEPT: $$\frac{(Machine_Power * Time)}{Work} = Constant$$
i.e. $$\frac{(M_1 * T_1)}{W_1} = \frac{(M_2 * T_2)}{W_2}$$

i.e. We only need once scenario in which specific number of machines can finish work in specific time

Statement 1: Each machine produces 200 components

Time and Rate are unknown hence
NOT SUFFICIENT

Statement 2: Two such machines, working at their constant rates, can produce 1,200 components in 9/2 hours

One scenario with rate and work is known hence the time of second case can be calculated as the work and Machines are already known
[2*(9/2)]/1200 = 6*T/1200

i.e. T = 3/2 Hours

SUFFICIENT

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Re: How many hours will it take 6 identical machines, working at their con   [#permalink] 03 Apr 2018, 01:07
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