Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0410:00 AM EDT
-11:59 PM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.
Sep 0712:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT- Sep 07
10:00 AM PDT
-11:00 AM PDT
A complete walkthrough of GMAT Club’s free 12-week GMAT study plan: what you study each week, how progress and goals are tracked, how the error log works, and how your practice unlocks paid tools at no cost. - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway - Sep 09
10:00 AM PDT
-11:00 AM PDT
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application... 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
24 Apr 2026, 13:09
Kudos
Bookmarks
This is such a good problem,
Here is how I solved it.
Basically even numbers have a common factor with 1000 so immediately 500 of them are gone (500 even integers are there from 1-1000).
Therefore the Odd numbers = 500,
In odd numbers, only numbers ending in 5 have a common divisor, numbers ending in 5 are odd multiples of 5
there are 200 multiples of 5 till 1000, 100 even and 100 odd, remove 100 odd multiples from the previously obtained 500
You get 400.
Here is how I solved it.
Basically even numbers have a common factor with 1000 so immediately 500 of them are gone (500 even integers are there from 1-1000).
Therefore the Odd numbers = 500,
In odd numbers, only numbers ending in 5 have a common divisor, numbers ending in 5 are odd multiples of 5
there are 200 multiples of 5 till 1000, 100 even and 100 odd, remove 100 odd multiples from the previously obtained 500
You get 400.
18 May 2026, 13:51
Kudos
Bookmarks
I tried this way.
all positive numbers less than 1000 which have no factors in common to 1000 other than 1=?
since 1000=2^3*5^3
first we must discard all even no.'s less than 1000 since have 2 as common factor=500 -1(for 1000)=499
then discard all odd multiples of 5 less than 1000,since even multiples are included in 499=> we have total of 200 multiples of 5 of which 100 should be odd ones i.e. 100 (no need to subtract 1 from this as 1000 not part of this)
so total discarded=499+100=599
hence required value=999-599=400
A
all positive numbers less than 1000 which have no factors in common to 1000 other than 1=?
since 1000=2^3*5^3
first we must discard all even no.'s less than 1000 since have 2 as common factor=500 -1(for 1000)=499
then discard all odd multiples of 5 less than 1000,since even multiples are included in 499=> we have total of 200 multiples of 5 of which 100 should be odd ones i.e. 100 (no need to subtract 1 from this as 1000 not part of this)
so total discarded=499+100=599
hence required value=999-599=400
A
22 May 2026, 02:19
Kudos
Bookmarks
Bunuel
This may sound a very very stupid question, but I want to ask, how do you figure out multiples of 2 and 5 in a given range? Like you have mentioned:
Multiples of 2 in the range 0-1000, not inclusive - \(\frac{998-2}{2}+1=499\);
Is there any formula for this? Or is it just some logic that I am unable to figure out?
