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# HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA

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Manager
Joined: 07 Feb 2010
Posts: 135
HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA  [#permalink]

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08 Oct 2010, 04:34
2
10
00:00

Difficulty:

65% (hard)

Question Stats:

59% (03:01) correct 41% (01:43) wrong based on 141 sessions

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HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA WORTH RS.30/KG SO THAT BY SELLING THE BLENDED VARIETY AT RS.30/KG THERE SHOULD BE A GAIN OF 10%

A) 36
B) 40
C) 32
D) 42
E) 45
Manager
Joined: 17 Apr 2010
Posts: 58
Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA  [#permalink]

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08 Oct 2010, 07:19
4

Let the wiight of tea(25 per kg) to be used - X
The total cost of the blend - total cost of 25 RS tea + total cost of 30 RS tea
- 25X + 900 ( as the total weight of 30 RS tea is already given i.e 30)
total weight of the blend = X + 30 ( which should be sold per 30 RS and result in 10% profit)

The equation follows like this

25X + 900 + (10 % of (25X + 900)) = 30( X + 30)
25X + 900 +2.5 X + 90 = 30 X + 900
27.5 X + 990 = 30 X + 900
2.5 X = 90
X= 90/2.5 = 36 .....Anwer is A

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Manager
Joined: 08 Sep 2010
Posts: 197
Location: India
WE 1: 6 Year, Telecom(GSM)
Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA  [#permalink]

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08 Oct 2010, 07:22
1
(x+30)*30=(110/100)(25x+30*30)

Solving we get 36.

Consider KUDOS if u like the solution.
Senior Manager
Joined: 06 Jun 2009
Posts: 313
Location: USA
WE 1: Engineering
Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA  [#permalink]

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08 Oct 2010, 08:01
3
(Cost Tea A) + (Cost Tea B) = (Cost New Tea)

25*x + 30*30 = 30/1.1 (x+30) = > x = 36

If cost of new tea is 30/1.1, then we can sell it at 30 for a 10% gain
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Intern
Joined: 26 Aug 2016
Posts: 8
Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA  [#permalink]

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16 Sep 2016, 10:14
Please I need to Know what went wrong in my solution

Price-Cost/Price=Profit Margin.

Hence, (900+30X)-(25x+900)/(900+30X)=10/100
so x = 45
Founder
Joined: 04 Dec 2002
Posts: 17243
Location: United States (WA)
GMAT 1: 750 Q49 V42
HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA  [#permalink]

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16 Sep 2016, 11:07
2
AhmedMera wrote:
Please I need to Know what went wrong in my solution

Price-Cost/Price=Profit Margin.

Hence, (900+30X)-(25x+900)/(900+30X)=10/100
so x = 45

Try backsolving - it is a good skill to practice and I think makes solving this question a lot easier

Our goal is to get to $27 per kg (approx) or 30/11 (This is the hardest part to figure out) 36kg*$25 + 30kg*$30 =$1800
$1800/66kg = 300/11 _________________ Founder of GMAT Club Just starting out with GMAT? Start here... OG2019 Directory is here! - New! Verbal OG2019 Directory is here! - New! Co-author of the GMAT Club tests Math Expert Joined: 02 Aug 2009 Posts: 6561 Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA [#permalink] ### Show Tags 16 Sep 2016, 11:36 2 AhmedMera wrote: Please I need to Know what went wrong in my solution Price-Cost/Price=Profit Margin. Hence, (900+30X)-(25x+900)/(900+30X)=10/100 so x = 45 Hi, You have gone wrong in your denominator.. Profit is always on COST, so profit = ( selling price -cost price)/ cost price.. (900+30x)-(25x+900)/(25x+900)= 10/100.. 5x/25x+900 =1/10....50x=25x+900....25x=900....x=36... _________________ 1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html GMAT online Tutor Intern Joined: 21 Dec 2014 Posts: 7 Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA [#permalink] ### Show Tags 16 Sep 2016, 16:24 1 Quote: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA WORTH RS.30/KG SO THAT BY SELLING THE BLENDED VARIETY AT RS.30/KG THERE SHOULD BE A GAIN OF 10% A) 36 B) 40 C) 32 D) 42 E) 45 Just figure out the last part and consider the question done. So the last part says " BY SELLING THE BLENDED VARIETY AT RS.30/KG THERE SHOULD BE A GAIN OF 10% " => $$30 = 1.1x => x = 300/11$$ where x is cost price of blended tea Using weighted avgs : $$25-------------------300/11-------------------30$$ Ratio of TEA WORTH RS.25/KG to TEA WORTH RS.30/KG = $$(30 - 300/11) / (300/11 - 25) = 6/5$$ So KGS OF TEA WORTH RS.25/KG = $$30 * 6/5 =36$$ Answer : A ___________________________________________________ +1 KUDOS if you like the solution Board of Directors Joined: 17 Jul 2014 Posts: 2717 Location: United States (IL) Concentration: Finance, Economics GMAT 1: 650 Q49 V30 GPA: 3.92 WE: General Management (Transportation) Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA [#permalink] ### Show Tags 21 Nov 2016, 09:24 anilnandyala wrote: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA WORTH RS.30/KG SO THAT BY SELLING THE BLENDED VARIETY AT RS.30/KG THERE SHOULD BE A GAIN OF 10% A) 36 B) 40 C) 32 D) 42 E) 45 the wording is very confusing, what is RS??? my approach... suppose we have 40 kgs of tea which costs 0.25$/kg
total revenue - 10$we have 30kgs of tea which costs 0.3$/kg
total revenue - 9$total - 19$
19 = 100%
1.9 = 10%
total new revenue = 20.9 must be.
40+30 = 70. 70*0.3 = 21 - too big. need a smaller number - B, D, and E are out.
since the difference is not that big (0.1$only), we should look for a number that is slightly less than 40. we are left with A and C...one more testing to do... let's take A 36*0.25 = 9$
30*0.3 = 9$total = 18$
+10% = 19.8$now..36+30 = 66. 66*0.3 = 19.8$ - we have a match...
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Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA  [#permalink]

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08 Jul 2018, 04:40
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Re: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA &nbs [#permalink] 08 Jul 2018, 04:40
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