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10 Dec 2020, 05:45
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
74% (02:37) correct
26%
(03:11)
wrong
based on 252
sessions
History
Date
Time
Result
Not Attempted Yet
How many kilograms of sugar costing $9 per kg must be mixed with 27kg of sugar costing $7 per kg so that there may be gain of 10% by selling the mixture at $9.24 per kg?
A. 77 kg
B. 60 kg
C. 63 kg
D. 50 kg
E. 47 kg
A. 77 kg
B. 60 kg
C. 63 kg
D. 50 kg
E. 47 kg
10 Dec 2020, 05:51
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Answer C
9.24*100/110=8.4
by using a method of an allegation
we get the ratio to be 7/3
27/3=9*7=63
9.24*100/110=8.4
by using a method of an allegation
we get the ratio to be 7/3
27/3=9*7=63
10 Dec 2020, 06:25
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Let 'a' be kilograms of sugar costing $9 per kg must be mixed to get 10% profit.
CP * Profit% = SP
(a*9+27*7)(110/100)=(a+27)*(9.24)
Therefore, a=63
Posted from my mobile device
CP * Profit% = SP
(a*9+27*7)(110/100)=(a+27)*(9.24)
Therefore, a=63
Posted from my mobile device
