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Bunuel
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I think statement (2) alone is sufficient.

Statement (1)

Route from D to M -> 130 miles
Route from M to G -> 110 miles

We cannot assume that the route from D to G passes through M. What if M is not on the route from D to G?

Then,

While statement (1) provides information about routes D->M and M->G, there is zero information about the route that exists from D->G.

Thus, insufficient.

Statement (2)

Say, time taken to cover the route length DG at a speed of 30 miles/hr = t

Given ->
30 x t = 45 x (t - 3)

t can be found. Then, the route length DG is simply 30t.

Thus, sufficient.



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TC97
How many miles long is the route from Danton to Griggston?

(1) It is 130 miles from Danton to Milton, which is 110 miles from Griggston.
DM=130, MG=110
we don't know the exact order among D,M,G
so we should consider all possible order
the order could be:
D->M->G or M->G->D, making DG=240
D->G->M or G->M->D, making DG=20
hence, insufficient.

(2) It will take 3 hours less to travel the entire route from Danton to Griggston at an average rate of 45 miles per hour than at an average of 30 miles per hour.
D=45*T=30*(T+3), T=6, D=45*6=270
hence, sufficient.

Answer: B
I would like to add one more case for statement 1, which is a triangle formation between DM and MG. And DG forming the Longest length. Sqrt (130^2+ 110^2 ) = 170.
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YES!! Thanks for adding that since I only consider those three in a straight line. Thanks!!
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TC97
How many miles long is the route from Danton to Griggston?

(1) It is 130 miles from Danton to Milton, which is 110 miles from Griggston.
DM=130, MG=110
we don't know the exact order among D,M,G
so we should consider all possible order
the order could be:
D->M->G or M->G->D, making DG=240
D->G->M or G->M->D, making DG=20
hence, insufficient.

(2) It will take 3 hours less to travel the entire route from Danton to Griggston at an average rate of 45 miles per hour than at an average of 30 miles per hour.
D=45*T=30*(T+3), T=6, D=45*6=270
hence, sufficient.

Answer: B
I would like to add one more case for statement 1, which is a triangle formation between DM and MG. And DG forming the Longest length. Sqrt (130^2+ 110^2 ) = 170.
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