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Re: How many odd factors does the number 2100 have ? [#permalink]
2100 = 2^2x3^1x5^2x7^1

except 2 all will give odd factors. So lets select only odd numbers power..
The number of odd factors are = (2+1)(1+1)(1+1) = 3x2x2 = 12

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Re: How many odd factors does the number 2100 have ? [#permalink]
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