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Re: How many pairs (x,y) exist for which y>x when x and y each can take th [#permalink]
CEO2021 wrote:
JerryAtDreamScore wrote:
Bunuel wrote:
How many pairs (x,y) exist for which y>x when x and y each can take the integer values from -10 to 9 inclusive?

(A) 180
(B) 190
(C) 200
(D) 210
(E) 220



Breaking Down the Info:

When y = -10, there are 0 x values.

When y = -9, there is 1 x value.

.....

When y = 10, there are 19 x values.

So we are adding 1, 2, 3, ..., 18, 19. That is \(\frac{1 + 19}{2}*19 = 190\)

[color=green]Answer: B[/col valor]


i think the above highlighted should be
"When y = 9, there are 19 x values"


CEO2021,

You are correct, minor typo by Jerry

Lets expand it.

\(9,8,7,6,5,4,3,2,1,0,-1,-2, -3,-4,-5,-6,-7,-8,-9,-10\)

So when \(y=9\) there are indeed \(19\) values of \(x \) from \(x=8\) to \(x= -10 \) inclusive

\(8-(-10)+1 =19\)
GMAT Club Bot
Re: How many pairs (x,y) exist for which y>x when x and y each can take th [#permalink]
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