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How many people bought TVs at the Electronics Depot?

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How many people bought TVs at the Electronics Depot?  [#permalink]

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New post 28 Sep 2017, 01:59
1
1
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

72% (01:09) correct 28% (01:13) wrong based on 181 sessions

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How many people bought TVs at the Electronics Depot?  [#permalink]

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New post 28 Sep 2017, 23:13
1
Statement 1) 1 in 6 bought a TV. We don't know how many customers so NOT SUFFICIENT.

Statement 2) Picking 4 people for a group out of a certain number of people would result in 126 combinations. Let's say there are K customers. K!/4!*(K-1)!=126. Deducing this gives us K=9. So we know number of Customers but we do not know how many bought TV.

Statement 1) Gives ratio of number of people who bought TV to Customers and Statement 2) Gives the number of customers.

So C, Both required but neither alone sufficient.
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Re: How many people bought TVs at the Electronics Depot?  [#permalink]

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New post 01 Feb 2019, 04:37
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[quote="rajudantuluri"]

Statement 2) Picking 4 people for a group out of a certain number of people would result in 126 combinations. Let's say there are K customers. K!/4!*(K-1)!=126. Deducing this gives us K=9. So we know number of Customers but we do not know how many bought TV.




Are you sure about the formula you used to solve Statement 2? shouldn't it be K!/4!*(K-4)!=126??
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Re: How many people bought TVs at the Electronics Depot?  [#permalink]

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New post 01 Feb 2019, 06:21
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Bunuel wrote:
How many people bought TVs at the Electronics Depot?

(1) One out of every six Electronics Depot customers bought a TV.
(2) If four Electronics Depot customers are chosen at random there are 126 different groups of people that could be chosen.

\(? = P\,\,\,\,\left( {{\rm{\# }}\,\,{\rm{bought - TV - there}}\,\,{\rm{people}}} \right)\)

\(\left( 1 \right)\,\,P = {N \over 6}\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,N = 6\,\,{\rm{customers}}\,\,\,\, \Rightarrow \,\,\,? = P = 1 \hfill \cr
\,{\rm{Take}}\,\,N = 12\,\,{\rm{customers}}\,\,\,\, \Rightarrow \,\,\,? = P = 2 \hfill \cr} \right.\,\,\,\,\,\,\,\,\,\,\,\left( {N = \# \,\,{\rm{customers}}\,\,{\rm{there}}} \right)\)

\(\left( 2 \right)\,\,C\left( {N,4} \right) = 126\,\,\,\,\, \Rightarrow \,\,\,\,\,N\,\,{\rm{unique}}\,\,\,\left( {{\rm{and}}\,\,N > 4\,\,{\rm{for}}\,\,{\rm{sure}}} \right)\,\,\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,P = 1\,\,\,\, \Rightarrow \,\,\,? = 1 \hfill \cr
\,{\rm{Take}}\,\,P = 2\,\,\,\, \Rightarrow \,\,\,? = 2 \hfill \cr} \right.\)

\(\left( {1 + 2} \right)\,\,{\rm{unique}}\,\,N\,\, = 6P\,\,\,\,\, \Rightarrow \,\,\,\,\,P\,\,{\rm{unique}}\)


The correct answer is therefore (C), indeed.


We follow the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: How many people bought TVs at the Electronics Depot?   [#permalink] 01 Feb 2019, 06:21
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