How many positive integers with distinct digits have the product of th

Question

How many positive integers with distinct digits have the product of their digits equal to 28?

A. 4
B. 6
C. 7
D. 8
E. 12

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GMATinsight · Answer

28 = 4*7 or 1*4*7

Numbers made up of digits 4, 7 = 2! = 2. {47 and 74}

Numbers made up of digits 1, 4, 7 = 3! = 6

Total Numbers = 2+6 = 8

Answer: Option D

Bunuel · Answer

________________________
Fixed. Thank you.

preetamsaha · Answer

Two digit numbers; The two digits can be 4 and 7: Two possibilities 47 and 74.
Three-digit numbers: The three digits can be 1, 4 and 7: 3! Or 6 possibilities.
We cannot have three digits as (2, 2, 7) as the digits have to be distinct.
We cannot have numbers with 4 digits or more without repeating the digits.
So, there are totally 8 numbers.

correct answer D

Kinshook · Answer

Asked: How many positive integers with distinct digits have the product of their digits equal to 28?

28 = 1*2*2*7= 1*4*7

Numbers = {47,74,147,174,714,417,471,741}

IMO D

How many positive integers with distinct digits have the product of th

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How many positive integers with distinct digits have the product of th

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615 to 715 in 15 Days (Ria's Strategies)

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