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I got the same answer with a different approach but I am not sure if it is by fluke, is this also correct:
I considered other prime numbers below 10 except 2 and 3 which is 5 and 7, 5 has: 100/5 = 20 multiples but 19 which are less than 100 7 has: 100/7 = 14.xx so around 14 multiples ,
I got the same answer with a different approach but I am not sure if it is by fluke, is this also correct:
I considered other prime numbers below 10 except 2 and 3 which is 5 and 7, 5 has: 100/5 = 20 multiples but 19 which are less than 100 7 has: 100/7 = 14.xx so around 14 multiples ,
Your solution doesn’t make sense. Why would adding the multiples of 5 and multiples of 7 give the count of numbers that are neither multiples of 2 nor multiples of 3?