jinx83
1) How many positive integers of four different digits, each greater than 3000, can be formed with the digits 1,2,3,4,5 and 6?
2) How many positive integers of three different digits, each less than 400 can be formed from the digits 1,2,3,4,5 and 6?
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One can do the way saxenashobhit proposed or:
1. How many positive integers of four different digits, each greater than 3000, can be formed with the digits 1, 2, 3, 4, 5 and 6?# of 4-digit numbers possible to form with 6 digits 1, 2, 3, 4, 5, and 6 is \(P^4_6=360\). As number must be more than 3,000 then it should start with 3, 4, 5, or 6 (with 4 out of 6 possible) --> so every 4 out of 6 number from 360 will fit --> \(\frac{4}{6}*360=240\).
2. How many positive integers of three different digits, each less than 400 can be formed from the digits 1, 2, 3, 4, 5 and 6?# of 3-digit numbers possible to form with 6 digits 1, 2, 3, 4, 5, and 6 is \(P^3_6=120\). As number must be less than 400 then it should start with 1, 2, or 3 (with 3 out of 6 possible) --> so every 3 out of 6 number from 240 will fit --> \(\frac{3}{6}*120=60\).
saxenashobhit
A)
Number of digits that can take different place
3 5 4 3
_ _ _ _
3*5*4*3 = 180 numbers
B
3 5 4
_ _ _
Number below 400 = 3*5*4 = 60
One typo: you should have 4 instead of 3.
Hope it's clear.