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# How many possible integer values are there for x if |4x - 3|

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How many possible integer values are there for x if |4x - 3| [#permalink]

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19 Dec 2004, 18:33
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How many possible integer values are there for x if |4x - 3| < 6 ?

A. One
B. Two
C. Three
D. Four
E. Five

[Reveal] Spoiler:
What I did here was to separate two scenarios:
a. 4x – 3 < 6 and
b. 4x – 3 > - 6

I simplified x in both scenarios that I ended up in a range of -2.25 < x < .75
Therefore, my answer is 3 integers (-2, -1, 0)

I would like to know if this method is correct and if I should use such method for problems that involve absolute value and inequality.
[Reveal] Spoiler: OA

Last edited by Bunuel on 20 Oct 2013, 04:03, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
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19 Dec 2004, 22:34
u can do this way. Directly substitute the value of x by trial and error method . Start from 0 and move on. u will get 0,1 and 2 as it asked for positive integers
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21 Dec 2004, 04:21
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Cpcalanoc you choose the right way BUT from 4x-3<6 => 4x<9 =>
x<2.25
the same mistake in the other

So -0.75 < x < 2.25
then the answer (0, 1, 2)

to Rakesh1239 your answer is right but where you see the word positive?
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Re: How many possible integer values are there for x, if I 4x 3 [#permalink]

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19 Oct 2013, 23:28
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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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20 Oct 2013, 04:08
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How many possible integer values are there for x if |4x - 3| < 6 ?

A. One
B. Two
C. Three
D. Four
E. Five

$$|4x - 3| < 6$$;

Get rid of the modulus: $$-6<4x-3< 6$$;

Add 3 to all three parts: $$-3<4x< 9$$;

Divide by 4: $$-\frac{3}{4}<x< \frac{9}{4}$$ --> $$-0.75<x< 2.25$$.

x can take following integer values: 0, 1, and 2.

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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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20 Nov 2013, 05:25
cpcalanoc wrote:
How many possible integer values are there for x if |4x - 3| < 6 ?

A. One
B. Two
C. Three
D. Four
E. Five

[Reveal] Spoiler:
What I did here was to separate two scenarios:
a. 4x – 3 < 6 and
b. 4x – 3 > - 6

I simplified x in both scenarios that I ended up in a range of -2.25 < x < .75
Therefore, my answer is 3 integers (-2, -1, 0)

I would like to know if this method is correct and if I should use such method for problems that involve absolute value and inequality.

You can try algebraically, If x>=0, then you will have the range 0<=x<9/4
If x<0, you get x>3/4 but this solution is not valid so x must vbe x>=0. Hence, you have 3 integer solutions from the above inequality: 0, 1 and 2.

Hope this helps
Cheers
J
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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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26 Mar 2014, 09:06
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[quote="cpcalanoc"]How many possible integer values are there for x if |4x - 3| < 6 ?

A. One
B. Two
C. Three
D. Four
E. Five

Solution: |4x-3| < 6

let 4x=a therefore we have |a-3| < 6 ==> read this as origin is at +3 and we have to move +6 to the right and -6 to the left

(the less than sign represents that the a must be within boundaries )

(3-6)----------3----------(3+6)

now, we have -3<a<9

but a =4x ==> -3<4x<9

dividing all values by +4 we have -0.75 <x < 2.24

Now question says Integer values (not rational ) therefore we have 0,1,2

Hence 3
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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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11 Apr 2014, 07:29
My Strategy , X is an integer ( + , - , 0 )
Principles : Integers ,Module and Inequality
Plug In Method Start with 0 , 1 , -1 , 2 as values
By Plugging in |4x - 3| < 6 Is Yes for 0 , 1, 2 But not with -1 So 3 Values

After seeing Bunnel solution we can use Module Basics with a Range in Number line
-6<4x - 3< 6 , -3<4x<9 , \frac {3}{4} <x< \frac{9}{4}, So - 0,75<x< 2.25
So Range from 0 , 1 , 2

If any wrong or any Suggestions in my Strategy pls Correct it
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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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11 Apr 2014, 12:12
kanusha wrote:
My Strategy , X is an integer ( + , - , 0 )
Principles : Integers ,Module and Inequality
Plug In Method Start with 0 , 1 , -1 , 2 as values
By Plugging in |4x - 3| < 6 Is Yes for 0 , 1, 2 But not with -1 So 3 Values

After seeing Bunnel solution we can use Module Basics with a Range in Number line
-6<4x - 3< 6 , -3<4x<9 , \frac {3}{4} <x< \frac{9}{4}, So - 0,75<x< 2.25
So Range from 0 , 1 , 2

If any wrong or any Suggestions in my Strategy pls Correct it

your strategy is good but suppose if you have lot of integers, how many will you keep plugging?

The second method is better as you quickly know the range and based on conceptual understanding.

given 4x - 3 can take both positive and negative values. It can lie between -6 and 0 or 0 and +6.
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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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27 Apr 2014, 09:58
Bunuel wrote:
How many possible integer values are there for x if |4x - 3| < 6 ?

A. One
B. Two
C. Three
D. Four
E. Five

$$|4x - 3| < 6$$;

Get rid of the modulus: $$-6<4x-3< 6$$;

Add 3 to all three parts: $$-3<4x< 9$$;

Divide by 4: $$-\frac{3}{4}<x< \frac{9}{4}$$ --> $$-0.75<x< 2.25$$.

x can take following integer values: 0, 1, and 2.

@Bunuel - The question stems talks about how many positive integer values of x. IF we are talking about positive integer then it should be only {1,2} and not {0).
Am I missing anything here?
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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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28 Apr 2014, 01:34
chanakya84 wrote:
Bunuel wrote:
How many possible integer values are there for x if |4x - 3| < 6 ?

A. One
B. Two
C. Three
D. Four
E. Five

$$|4x - 3| < 6$$;

Get rid of the modulus: $$-6<4x-3< 6$$;

Add 3 to all three parts: $$-3<4x< 9$$;

Divide by 4: $$-\frac{3}{4}<x< \frac{9}{4}$$ --> $$-0.75<x< 2.25$$.

x can take following integer values: 0, 1, and 2.

@Bunuel - The question stems talks about how many positive integer values of x. IF we are talking about positive integer then it should be only {1,2} and not {0).
Am I missing anything here?

The question does not specify that the integers must be positive: "how many possible integer values are there for x..."

Hope it's clear.
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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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28 Apr 2014, 06:46
Bunuel wrote:
chanakya84 wrote:
Bunuel wrote:
How many possible integer values are there for x if |4x - 3| < 6 ?

A. One
B. Two
C. Three
D. Four
E. Five

$$|4x - 3| < 6$$;

Get rid of the modulus: $$-6<4x-3< 6$$;

Add 3 to all three parts: $$-3<4x< 9$$;

Divide by 4: $$-\frac{3}{4}<x< \frac{9}{4}$$ --> $$-0.75<x< 2.25$$.

x can take following integer values: 0, 1, and 2.

@Bunuel - The question stems talks about how many positive integer values of x. IF we are talking about positive integer then it should be only {1,2} and not {0).
Am I missing anything here?

The question does not specify that the integers must be positive: "how many possible integer values are there for x..."

Hope it's clear.

Ahh..my mistake....
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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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03 Nov 2015, 04:30
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: How many possible integer values are there for x if |4x - 3| [#permalink]

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31 Oct 2016, 13:59
You can figure this out by taking the equation and solving:

SCENARIO 1:
(4x - 3) < 6
4x<9
x<(9/4)

SCENARIO 2:
(4x - 3) > -6
4x>-3
x>(-3/4)

So (-0.75)<x<2.25 --> The only integers within this range are 0,1,2 --> Hence, 3 is the correct answer (C)
Re: How many possible integer values are there for x if |4x - 3|   [#permalink] 31 Oct 2016, 13:59
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