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Bunuel
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Graphical approach is much better
We can easily draw the graph of y=||x-3|-2| by the following steps:-
Step 1:We will first draw a line which has slope 1 and y intercept -3 (y=x-3)
Step 2:Then we would flip the line over x axis. This would result in a 'V' shaped graph with vertex(of 'V') on x=3. This is the graph of y=|x-3|
Step 3:Then we will shift the V shaped Line 2 units down which would result in the graph of y=|x-3|-2
Step 4: Further we will again flip the graph over x axis to get a 'W' shaped graph. This is finally the graph of y=||x-3|-2|

We would find the number of intersection points of this graph with the line y=1 (line || x axis) to finally get the answer

NOTE- In question if it is asked 'no. of solutions', then graphical method is the best and hassle-free approach. But if it would ask the values of those soultions then we need to solve by cases
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Bunuel can you please provide a solution to this
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We need to find how many solutions does the equation ||x - 3| - 2| = 1 have?

Now, | |x - 3| - 2 | = 1
=> |x - 3| - 2 = 1 or -1

Now we have |x - 3| = 3 or 1
-Case 1: |x - 3| = 3
=> x - 3 = 3 or -3
=> x = 6, 0 is a SOLUTION
-Case 2: |x - 3| = 1
=> x - 3 = 1 or -1
=> x = 4, 2 is a SOLUTION

So, there are four solutions for x = 0, 2, 4, 6

So, Answer will be E
Hope it helps!

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