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18 Sep 2019, 05:13
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
42% (01:09) correct
58%
(01:18)
wrong
based on 81
sessions
History
Date
Time
Result
Not Attempted Yet
How many ways can 4 different prizes be given away to 3 boys, if each boy is eligible for all the prizes?
A. 81
B. 64
C. 48
D. 27
E. 12
A. 81
B. 64
C. 48
D. 27
E. 12
firas92
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18 Sep 2019, 05:21
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Let the prizes be A, B, C & D
A can be given to Boy 1 or Boy 2 or Boy 3 - 3 Options
B can be given to Boy 1 or Boy 2 or Boy 3 - 3 Options
C can be given to Boy 1 or Boy 2 or Boy 3 - 3 Options
D can be given to Boy 1 or Boy 2 or Boy 3 - 3 Options
Therefore the total number of outcomes is 3*3*3*3=81
Answer is (A)
A can be given to Boy 1 or Boy 2 or Boy 3 - 3 Options
B can be given to Boy 1 or Boy 2 or Boy 3 - 3 Options
C can be given to Boy 1 or Boy 2 or Boy 3 - 3 Options
D can be given to Boy 1 or Boy 2 or Boy 3 - 3 Options
Therefore the total number of outcomes is 3*3*3*3=81
Answer is (A)
18 Sep 2019, 06:37
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How many ways can 4 different prizes be given away to 3 boys, if each boy is eligible for all the prizes?
A. 81
B. 64
C. 48
D. 27
E. 12[/quote]
Each boy(3) is eligible for all the 4 different prizes. So no of ways 3^4 = 81
A. 81
B. 64
C. 48
D. 27
E. 12[/quote]
Each boy(3) is eligible for all the 4 different prizes. So no of ways 3^4 = 81
