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How much space, in cubic units, is left vacant when maximum number of

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How much space, in cubic units, is left vacant when maximum number of  [#permalink]

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New post 01 Nov 2019, 04:54
1
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A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

59% (02:10) correct 41% (01:45) wrong based on 86 sessions

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Re: How much space, in cubic units, is left vacant when maximum number of  [#permalink]

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New post 01 Nov 2019, 05:12
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Bunuel wrote:
How much space, in cubic units, is left vacant when maximum number of 4x4x4 cubes are fitted in a rectangular box measuring 10x12x16 ?

A. 0
B. 36
C. 180
D. 216
E. 384


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Total space = 10x12x16
In any orientation, space used will be 12x16x8
—> Space left out = 12x16x10 - 12x16x8 = 12x16x2 = 384

IMO Option E

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Re: How much space, in cubic units, is left vacant when maximum number of  [#permalink]

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New post 02 Nov 2019, 01:38
Bunuel wrote:
How much space, in cubic units, is left vacant when maximum number of 4x4x4 cubes are fitted in a rectangular box measuring 10x12x16 ?

A. 0
B. 36
C. 180
D. 216
E. 384


Are You Up For the Challenge: 700 Level Questions


total volume of the box ; 12*16*10
total volume of the cube which can fit into the box ; 12*16*8
8 because that is the max dimension of the cube of 4 can cover for space of 10
so ∆ will be 12*16*10- 12*16*8 = 384
IMO E
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Re: How much space, in cubic units, is left vacant when maximum number of  [#permalink]

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New post 24 Jan 2020, 04:49
10*12*16. We will be able to use all of 12 and 16 but only 8 out of 10.

So Area remaining is 2*12*16=384

Option E
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Re: How much space, in cubic units, is left vacant when maximum number of  [#permalink]

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New post 25 Jan 2020, 09:51
Bunuel wrote:
How much space, in cubic units, is left vacant when maximum number of 4x4x4 cubes are fitted in a rectangular box measuring 10x12x16 ?

A. 0
B. 36
C. 180
D. 216
E. 384


Are You Up For the Challenge: 700 Level Questions


The rectangular box is 10 x 12 x 16. For the side length of 10: We can occupy two lengths of 4's. Subtract the two four's and 2 is left.
For the side length of 12: We can occupy the entire area with three 4's.
For the side length of 16: We can occupy the entire area with four 4's.

Imagine the length of 10 as the height, when we fill this box up, we have the entire base of 12 * 16 filled with a height 2 missing. Therefore after filling up the rectangular box, we will just be left with a volume 2 * 12 * 16 left, 2 * 12 * 16 = 384.

(Note this doesn't translate over when two sides are not fully covered, we simply subtract volumes at that point).

Ans: E
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Re: How much space, in cubic units, is left vacant when maximum number of   [#permalink] 25 Jan 2020, 09:51
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