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03 Jan 2020, 02:22
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
54% (03:06) correct
46%
(03:07)
wrong
based on 148
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How much time will an express train of length 150 meters and running at a speed of 75 kmph take to cross a man walking at 5 m/s inside a passenger train of length 200 meters and running at 15 kmph in a direction opposite to that of the express train. The man is walking inside the train and in opposite direction to that of the train. (Assume the man does not reach the end of his train meanwhile.)
A. 5 sec
B. 6 sec
C. 7.5 sec
D. 8 sec
E. 10 sec
A. 5 sec
B. 6 sec
C. 7.5 sec
D. 8 sec
E. 10 sec
14 Jul 2021, 01:11
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ishant5243
It's a very simple question if you ignore the length of the passenger train altogether. Just assume that there is an express train running at 75 km/hr and you need to calculate the time it needs to overtake a person walking/running in the same direction on road at speed of 3km/hr( speed of the person in train(18km/hr) - speed of passenger train in opposite direction(15km/hr)).
So now all you need is to divide the length of the express train(150 m) with the relative speed of the express train and person - 72km/hr.
(150*60*60)/72*1000 = 7.5 sec
Please help with Kudos if it helps.
It's a very simple question if you ignore the length of the passenger train altogether. Just assume that there is an express train running at 75 km/hr and you need to calculate the time it needs to overtake a person walking/running in the same direction on road at speed of 3km/hr( speed of the person in train(18km/hr) - speed of passenger train in opposite direction(15km/hr)).
So now all you need is to divide the length of the express train(150 m) with the relative speed of the express train and person - 72km/hr.
(150*60*60)/72*1000 = 7.5 sec
Please help with Kudos if it helps.
General Discussion
03 Jan 2020, 11:35
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Bunuel
The speed of the express train is the opposite of that of the passenger train and the man walking inside the passenger train.
Therefore the other two speeds are working against the express train.
We can add all the speeds together and treat the entire system as one object. Hence treating the man and passenger train as stationary, the express train has a speed of:
75 km/h + 15 km/h + 5 m/s = 90 km/h + 5 m/s = 90 * 5/18 m/s + 5 m/s = 30 m/s.
The total distance we need to travel however is only 150 meters since the express train is only 150 meters long (or think of it as the time needed for the man to pass the 150-meter express train). Therefore 150 m / (30 m/s) = 5s is the answer.
Ans: A
