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10 Dec 2020, 03:15
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C
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Difficulty:
65%
(hard)
Question Stats:
63% (02:44) correct
37%
(02:46)
wrong
based on 273
sessions
History
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Not Attempted Yet
How much water must be added to 60 litres of milk at 1.5 litres for $20 So as to have a mixture worth $\(10\frac{2}{3}\) a litre?
A. 10 litres
B. 12 litres
C. 15 litres
D. 18 litres
E. 20 litres
A. 10 litres
B. 12 litres
C. 15 litres
D. 18 litres
E. 20 litres
10 Dec 2020, 21:37
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Bunuel
CP of 1.5 Liters of milk = $20
CP of 60 liters milk = \(\frac{60 * 20}{1.5} = $800\)
CP of water is assumed to be 0
Let x liters of water be added. Average CP = \(\frac{32}{3} = \frac{800 + 0}{60 + x}\)
(60 + x) * 32 = 3 * 800
1920 + 32x = 2400
32x = 480
x = 15 liters
Option C
Arun Kumar
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Joined: 02 Nov 2020
Last visit: 18 May 2026
Posts: 112
Given Kudos: 1,150
Location: India
Schools: Yale '20 (D)
GMAT 1: 220 Q2 V2
16 Dec 2020, 23:12
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1.5 L of milk for 20$
1 L -> 20/1.5 = 40/3 $
Mixture is for 10*2/3 $ = 32/3 $
I am assuming i will be getting water for free.
Now have a look at the screenshot-
so water and milk are in the ratio of 1:4
If milk is 60 L, water will be 15 L
1 L -> 20/1.5 = 40/3 $
Mixture is for 10*2/3 $ = 32/3 $
I am assuming i will be getting water for free.
Now have a look at the screenshot-
so water and milk are in the ratio of 1:4
If milk is 60 L, water will be 15 L
Attachments
Mixture and alligation.PNG [ 10.43 KiB | Viewed 29317 times ]
