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# I am having a hard time understanding the wording of this Q,

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Manager
Joined: 28 Aug 2008
Posts: 101

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I am having a hard time understanding the wording of this Q, [#permalink]

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12 Sep 2008, 10:40
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I am having a hard time understanding the wording of this Q, can anyone please explain?

For any positive integer x, the 2-height of x is defined to be the greatest nonnegative integer n such that 2^n is a factor of x. If k and m are positive integers, is the 2-height of k greater than the 2-height of m?

1) k>m

2) k/m is an even integer

Kudos [?]: 43 [0], given: 0

SVP
Joined: 29 Aug 2007
Posts: 2472

Kudos [?]: 842 [0], given: 19

Re: DS - Integers and Factors [#permalink]

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12 Sep 2008, 10:49
IgnitedMind wrote:
I am having a hard time understanding the wording of this Q, can anyone please explain?

For any positive integer x, the 2-height of x is defined to be the greatest nonnegative integer n such that 2^n is a factor of x. If k and m are positive integers, is the 2-height of k greater than the 2-height of m?

1) k>m

2) k/m is an even integer

1: k = 48 and m = 16
2^n for k and m 2^4

if k = 32 and m = 16
2^n for k = 2^5
2^n for m = 2^4
so nsf.

B. if k > m and k/m is an even integer, the 2^n for k must be > 2^n for m because k has more 2's than m.

so 2^n for k > 2^n for m.

//B//
_________________

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GT

Kudos [?]: 842 [0], given: 19

Manager
Joined: 28 Aug 2008
Posts: 101

Kudos [?]: 43 [0], given: 0

Re: DS - Integers and Factors [#permalink]

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12 Sep 2008, 11:27
Correct.. OA is B

This is simple... I guess I had a hard time converting the word too math, I was looking too much into it.. lol

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Re: DS - Integers and Factors   [#permalink] 12 Sep 2008, 11:27
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# I am having a hard time understanding the wording of this Q,

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