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rgajare14
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itsme291
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itsme291
I did this with lines and co-ordinate axis, which took me much less time. But its kinda hard to explain here.
Still if it helps, draw two lines corresponding to the inequalities and check for the regions they are covering.

which co-ordinate do you see these lines ? it would be interesting to see that approach but I can't put it on the paper correctly :-(
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rgajare14
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rpmodi, If as per question, x - 2y < -6 , wouldn't it be incorrect to say x - 2y = 7. ??
Did you mean x -2y = -7.

And following that Subtracting 2y from x has yielded a smaller number (-7) as compared to subtracting y, from x, which yielded -1.
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rgajare14
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itsme291
I did this with lines and co-ordinate axis, which took me much less time. But its kinda hard to explain here.
Still if it helps, draw two lines corresponding to the inequalities and check for the regions they are covering.

Wow interesting...I tried to plot lines on a co ordinate system for the above equations..But those did not lead me anywhere. So I am clueless w.r.t your explanation right now..
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rpmodi
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rgajare14
rpmodi, If as per question, x - 2y < -6 , wouldn't it be incorrect to say x - 2y = 7. ??
Did you mean x -2y = -7.

And following that Subtracting 2y from x has yielded a smaller number (-7) as compared to subtracting y, from x, which yielded -1.


ya I meant we can assume x-2y=-7 and x-y=-1 following that y would be +ve and x would be +ve
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itsme291
I did this with lines and co-ordinate axis, which took me much less time. But its kinda hard to explain here.
Still if it helps, draw two lines corresponding to the inequalities and check for the regions they are covering.

Wow interesting...I tried to plot lines on a co ordinate system for the above equations..But those did not lead me anywhere. So I am clueless w.r.t your explanation right now..

Wil l try to make a diagram and explain....
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itsme291
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We know the sign of xy, if on a co-ordinate axis, we know which quadrant x and y lies in.
(i.e. whether they are both +ve, or both –ve or +ve and -ve).
See the diagram attached. Blue line is the line x-y=-2 and the blue region shows the inequality.
Same for the red line and red region, which represents the equation x-2y<-6.
Both the statements individually don’t give us anything as the sign of xy will vary.
But the common area to the both lies only in quadrant 1, which means that taking both the inequalities, x>0 and y>0

Hence we can say that xy>0

Hope this explains 
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rgajare14
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itsme291
We know the sign of xy, if on a co-ordinate axis, we know which quadrant x and y lies in.
(i.e. whether they are both +ve, or both –ve or +ve and -ve).
See the diagram attached. Blue line is the line x-y=-2 and the blue region shows the inequality.
Same for the red line and red region, which represents the equation x-2y<-6.
Both the statements individually don’t give us anything as the sign of xy will vary.
But the common area to the both lies only in quadrant 1, which means that taking both the inequalities, x>0 and y>0

Hence we can say that xy>0

Hope this explains 

Excellent ! Got you...What a novel way !
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bmn111
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itsme291
But the common area to the both lies only in quadrant 1, which means that taking both the inequalities, x>0 and y>0

Hence we can say that xy>0

Hope this explains 


This is simply brilliant! I feel like I've just added a major weapon with this type of DS questions.



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