Official Solution: Bunuel
Phyllis, Shania, and Taneisha are each working at a constant rate to fill envelopes for a local city council letter mailing informational campaign. Shania would take 3 hours to complete the job alone, and Taneisha can complete the job faster than Phyllis.
If Phyllis, Shania, and Taneisha, working together, can complete the job in 1 hour, select for
Phyllis the time in hours she would take to complete the job alone, and select for
Taneisha the time in hours she would take to complete the job alone that are jointly consistent with the information provided. Make only two selections, one in each column.
Since it takes Shania 3 hours to complete the job alone, in 1 hour she'd complete \(\frac{1}{3}\) of the job, leaving \(\frac{2}{3}\) of the job to be completed by Phyllis and Taneisha. One being faster than the other implies that the faster one, Taneisha, can complete the job in less than 3 hours, and the slower one, Phyllis, can complete the job in more than 3 hours.
Among the options, the times less than 3 hours are 1 hour and 2 hours. If Taneisha took 1 hour, she would be able to finish the entire job alone in 1 hour, which cannot be true since the problem states all three together take 1 hour. Therefore, the only consistent option is that Taneisha takes 2 hours to complete the job alone.
Assuming Phyllis takes \(p\) hours to complete the job alone, we'd have (Taneisha's rate) + (Phyllis's rate) \(= \frac{1}{2} + \frac{1}{p} = \frac{2}{3}\), which gives \(p = 6\) hours.
Correct answer: Phyllis
"6"Taneisha
"2"