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13 Jul 2020, 03:47
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
42% (01:37) correct
58%
(01:54)
wrong
based on 193
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If 0 < x < 100, what is the value of x?
(1) \(\sqrt{x}\) is a multiple of 8.
(2) \(\sqrt{x}\) and \(\sqrt[3]{x}\) are integers.
Are You Up For the Challenge: 700 Level Questions
(1) \(\sqrt{x}\) is a multiple of 8.
(2) \(\sqrt{x}\) and \(\sqrt[3]{x}\) are integers.
Are You Up For the Challenge: 700 Level Questions
Updated on: 13 Jul 2020, 22:55
Originally posted by GMATinsight on 13 Jul 2020, 03:52.
Last edited by GMATinsight on 13 Jul 2020, 22:55, edited 2 times in total.
Last edited by GMATinsight on 13 Jul 2020, 22:55, edited 2 times in total.
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Bunuel
Statement 1: \(\sqrt{x}\) is a multiple of 8.
i.e. \(√x = 8, 16, 24, 32\)...
ie.. \(x = 64, 256\)..
ie.. \(x = 64\) in the given range
SUFFICINT
Statement 2: \(\sqrt{x}\) and \(\sqrt[3]{x}\) are integers.
i.e. x is a perfect square as well as a perfect cube
ie.. \(x = 1^6\) or \(2^6\) or \(3^6\) or...
But less than 100 x can only be \(1^6\) or \(2^6\)
NOT SUFFICINT
Answer: Option A
13 Jul 2020, 03:53
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Bunuel
Asked: If 0 < x < 100, what is the value of x?
(1) \(\sqrt{x}\) is a multiple of 8.
\(x = 64k^2\)
x = 64
SUFFICIENT
(2) \(\sqrt{x}\) and \(\sqrt[3]{x}\) are integers.
\(x = I^6\)
where I is an integer
I = {1,2}
x = {1,64}
NOT SUFFICIENT
IMO A
