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16 Sep 2021, 02:15
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
89% (01:09) correct
11%
(01:40)
wrong
based on 81
sessions
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If \(\frac{1}{3} +\frac{1}{6}+\frac{1}{9}=\frac{22}{x}\), which of the following must be an integer?
I. \(\frac{x}{8}\)
II. \(\frac{x}{12}\)
II. \(\frac{x}{24}\)
(A) I only
(B) II only
(C) I and III only
(D) II and III only
(E) I, II, and III
I. \(\frac{x}{8}\)
II. \(\frac{x}{12}\)
II. \(\frac{x}{24}\)
(A) I only
(B) II only
(C) I and III only
(D) II and III only
(E) I, II, and III
16 Sep 2021, 02:49
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\(\frac{1}{3} +\frac{1}{6}+\frac{1}{9}=\frac{22}{x}\)
\(\frac{11}{18}=\frac{22}{x}\)
\(x=\frac{22*18}{11} = 36\)
I. \(\frac{x}{8} = 4.5\)
II. \(\frac{x}{12} = 3\)
III. \(\frac{x}{24} = 1.5\)
II only is an integer. Hence, OA is (B).
\(\frac{11}{18}=\frac{22}{x}\)
\(x=\frac{22*18}{11} = 36\)
I. \(\frac{x}{8} = 4.5\)
II. \(\frac{x}{12} = 3\)
III. \(\frac{x}{24} = 1.5\)
II only is an integer. Hence, OA is (B).
16 Sep 2021, 03:52
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\(\frac{1}{3} +\frac{1}{6}+\frac{1}{9}=\frac{22}{x}\)
=> \(\frac{1*6+1*3+1*2}{18}=\frac{22}{x}\)
=> \(\frac{11}{18}=\frac{22}{x}\)
=> \(x=\frac{22*18}{11} = 36\)
I. \(\frac{x}{8} = 4.5\)
II. \(\frac{x}{12} = 3\)
III. \(\frac{x}{24} = 1.5\)
Only II is an integer. Choice B.
=> \(\frac{1*6+1*3+1*2}{18}=\frac{22}{x}\)
=> \(\frac{11}{18}=\frac{22}{x}\)
=> \(x=\frac{22*18}{11} = 36\)
I. \(\frac{x}{8} = 4.5\)
II. \(\frac{x}{12} = 3\)
III. \(\frac{x}{24} = 1.5\)
Only II is an integer. Choice B.
