If 1 < d <2, is the tenths’ digit of the decimal representation of d equal to 9?

(1) d + 0.01 <2 --> d<1.99 --> 1<d<1.99. The tenths' digit of d may or may not be 9, consider d=1.98 and d=1.1. Not sufficient.

(2) d + 0.05 > 2 --> d>1.95 --> 1.95<d<2. Each number from this range has 9 as its tenths' digit. Sufficient.

Answer: B.

1234.567

1 - THOUSANDS
2 - HUNDREDS
3 - TENS
4 - UNITS
. - decimal point
5 - TENTHS
6 - HUNDREDTHS
7 - THOUSANDTHS

Hope it's clear.
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Hi =)

Try this way:

(1) d + 0.01 < 2 ; d < 1,99 It is clearly insufficient since the tenths number can be between 0 and 9

(2) d + 0.05 > 2 ; d >1,95 So you know that the tenths number must be 9 even if there is a number of infinite possibilities between 1,95 and 2

So B is sufficient!

Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If 1 < d < 2, is the tenths’ digit of the decimal representation of d equal to 9?

(1) d + 0.01 < 2
(2) d + 0.05 > 2


In the original condition, there is 1 variable(d), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer.
For 1), d=1.9 -> yes, 1.8 -> no, which is no and not sufficient.
For 2), if d=1.8..., d+0.05>2 is impossible. So it always has to be d=1.9..., which is yes and sufficient. Therefore, the answer is B.


-> For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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The thing to remember here is that Atmost carry in any division is 1
hence B is sufficent
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I am not able to understand how its B. If d=1.90+0.05 then its not greater than 2 . Which make it insufficient.Please explain.

When picking numbers you should pick them so that they satisfy the stem and the statement you are testing. Does your example satisfy the second statement, which you are trying to test?
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Given: 1 < d < 2

Target question: Is the tenths’ digit of the decimal representation of d equal to 9?

Statement 1: d + 0.01 < 2
Subtract 0.01 from both sides of the inequality to get: d < 1.99
So, it could be the case that d = 1.93, in which case the answer to the target question is YES, the tenths digit is 9
Or it could be the case that d = 1.77, in which case the answer to the target question is NO, the tenths digit is not 9
Since we can’t answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: d + 0.05 > 2
Subtract 0.05 from both sides of the inequality to get: d > 1.95
Since we already know that d < 2, we can combine these inequalities to get: 1.95 < d < 2
So, it MUST be the case that the tenths digit is 9
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer: B

Cheers,
Brent
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Question: If 1 < d < 2, is the tenths’ digit of the decimal representation of d equal to 9?

How can we determine the tenths' digit? We need to have some information about the hundredths' digit. Lets take a look at the choices:

(1) d + 0.01 < 2

d + 0.01 could be 1.91
d + 0.01 could be 1.41

INSUFFICIENT.

(2) d + 0.05 > 2

d + 0.05 is GREATER THAN 2.
We can conclude d must between 1.95 and 2.

for example: 1.96 + 0.05 > 2

SUFFICIENT.

Answer is B.
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1) just tells us that d < 1.99
But it can be anything 1.98, 1.97 even 1.87, etc, INSUFF

2) tells us that the d>1.95 so either of 1.96, 1.97, 1.98 or 1.99 (since d also has to be < 2)
in each of the 4 cases, tenth digit is 9, so SUFF