Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
17 Mar 2021, 14:23
Kudos
Bookmarks
Any side of triangle is less than the sum of other two sides so in this case \(x < 22.\)
Also any side of triangle is larger than positive difference of other two sides so \(x > 2\).
\(2 < x < 22\)
Total of \(19\) possible values.
Given that the triangle is acute, hence
\(AB^2 + BC^2 > AC^2\)
Case 1:-
\(10^2 + x^2 > 12^2\)
\(x^2 > 144 - 100 = 44\)
hence, \(x^2 > 44\) means.... \(x>6\)
Case 2:-
\(10^2 + 12^2 > x^2\)
\(x^2 < 244\)
\(x<16\)
hence \(x = 7,8,9,10,11,12,13,14,15 => 9 \) triangles
Also any side of triangle is larger than positive difference of other two sides so \(x > 2\).
\(2 < x < 22\)
Total of \(19\) possible values.
Given that the triangle is acute, hence
\(AB^2 + BC^2 > AC^2\)
Case 1:-
\(10^2 + x^2 > 12^2\)
\(x^2 > 144 - 100 = 44\)
hence, \(x^2 > 44\) means.... \(x>6\)
Case 2:-
\(10^2 + 12^2 > x^2\)
\(x^2 < 244\)
\(x<16\)
hence \(x = 7,8,9,10,11,12,13,14,15 => 9 \) triangles
Jaya6
Joined: 09 Jan 2021
Last visit: 21 Jun 2022
Posts: 68
Own Kudos:
Given Kudos: 142
Location: India
Schools: ISB '23 (S)
GPA: 3.2
22 Mar 2021, 08:21
Kudos
Bookmarks
bangalorian2000
Hello,
could you please tell me how does the calculation work for right and obtuse angle in the same method?
15 Aug 2024, 16:51
Kudos
Bookmarks
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
