The formula for finding the number of powers of a prime number p, in the n! is

n/p+n/p^2+n/p^3 ... till p^x≤n (

https://gmatclub.com/forum/math-number- ... 88376.html)

Applying formula, p=2,n=10, x=3(since 2^3<10 but 2^4>10)

so, 10/2+10/4+10/8=5+2+1=8

So since 10! has 8 powers of 2, to make it odd, 2 in denominator needs to be raised to 8.

Option D

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