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Updated on: 27 May 2014, 13:31
Originally posted by kennavalkyrie on 27 May 2014, 12:51.
Last edited by Bunuel on 27 May 2014, 13:31, edited 1 time in total.
Last edited by Bunuel on 27 May 2014, 13:31, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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Difficulty:
5%
(low)
Question Stats:
88% (01:15) correct
12%
(01:57)
wrong
based on 213
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If 11m − n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?
(A) 2m −1
(B) 4m
(C) 6m
(D) m/5
(E) 6m/5
(A) 2m −1
(B) 4m
(C) 6m
(D) m/5
(E) 6m/5
The answer is 4m, but I got 2m, what did I do wrong?
I got: p=11m-n 11m-n-p+11m+p+n\frac{}{11}=22/11m=2m
n=-p+11m
m=p+n/11
I got: p=11m-n 11m-n-p+11m+p+n\frac{}{11}=22/11m=2m
n=-p+11m
m=p+n/11
27 May 2014, 13:15
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kennavalkyrie
Dear kennavalkyrie,
I'm happy to respond.
Unfortunately, the way you have presented your work is unclear enough that I cannot follow what you were thinking. I think part of the problem, in that last line, is that when you divide by 11, you need to divide every term. Relatedly, I think you are neglecting grouping symbols, and overlooking these core mathematical symbols leads to a large number of mistakes. See: https://magoosh.com/gmat/2013/gmat-quant ... g-symbols/
I will show you the solution:
11m - n = p
Add n to both sides:
11m = n + p
Add m to both sides:
12m = n + p + m
Now, divide both sides by 3
4m = (n + p + m)/3 = the average of n, p, and m
Does all this make sense?
Mike
General Discussion
27 May 2014, 13:31
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kennavalkyrie
If 11m − n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?
(A) 2m −1
(B) 4m
(C) 6m
(D) m/5
(E) 6m/5
The average of m, n, and p is \(\frac{m+n+p}{3}\).
Since 11m − n = p, then n + p = 11m. Substitute the value of n + p into the average expression: \(\frac{m+n+p}{3}=\frac{m+11m}{3}=\frac{12m}{3}=4m\).
Answer: B.
P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to rules 1, 3, 5, and 8. Thank you.
