devavrat wrote:
what happened to m root of 27 ??
How does 1 satisfy this equation?
1 satisfies only 4m>1
If m is put in the m root 27 = 3^3m equation how can the equation be solved???
Pls explain
It looks like you'll need to brush up on exponents.
\(\sqrt[m]{27}\) = \((3^{3})^{1/m} = 3^{3*(1/m)} = 3^{3/m}\)
They're telling us that \(3^{3/m} = 3^{3m}\)
For which answer choices does m satisfy 4m > 1?
(A) –4 > 1
(B) –1 > 1
(C) 0 > 1
(D) 1 > 1(E) 1\(3^{3/m} = 3^{3m}\) if we use 1 or -1 for m (using 0 gives us an invalid equation). So if we know that 4m > 1, then E must be the answer.