Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
The Problem description is not precise, could you provide clear problem solving strategy.
Thanks.
If 2s > 8 and 3t < 9, which of the following could be the value of s-t?
I. -1 II. 0 III. 1
A. None B. I only C. II only D. III only E. II and III
we have two equations.. 2s > 8 .. s>4, so' s' can be 4.1,5,5.05 etc and 3t < 9 .. t<3 so 't'can be 2.9999, 2,-1 etc..
if we take the lowest possible difference between s and t, we will take lowest value of s, which is just above 4 and highest value of t, which is just lower to 3.. s-t >4.0000000001 -2.999999999 .... so s-t>1 therefore all values of -1,0,1 are not possible ans none A hope it helped
_________________
I understand how we get s>4 and t<3, but I'm having a hard time wrapping my head around why t cannot be negative. Can someone please explain?
We don't need to check when t<0 but for the sake of your question, even if t <0 ---> -t>0 and you know that s>0, giving you s-t > 1 for all values of s and t as s>1
Any positive quantity added to a quantity >1 will give you the sum as >1
If 2s > 8 and 3t < 9, which of the following could be the value of s-t?
I. -1 II. 0 III. 1
A. None B. I only C. II only D. III only E. II and III
Given: 2s > 8 Divide both sides by 2 to get: s > 4
Given: 3t < 9 Divide both sides by 3 to get: t < 3
NOTE: If we have two inequalities with the inequality symbols facing in the same direction, we can add the inequalities to learn something new.
So, take t < 3 and multiply both sides by -1 to get: -t > -3[aside: when we divide or multiply both sides of an inequality by a NEGATIVE value, we mist REVERSE the symbol]
We now have: s > 4 -t > -3
When we ADD these two inequalities, we get: s - t > 1
If s - t > 1, then: I) s - t CANNOT equal -1 II) s - t CANNOT equal 0 III) s - t CANNOT equal 1