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# If -30 ≤ 6x ≤ 60 and 40 ≥ 2y + 4 ≥ 8, what is the greatest possible va

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Joined: 02 Sep 2009
Posts: 53061
If -30 ≤ 6x ≤ 60 and 40 ≥ 2y + 4 ≥ 8, what is the greatest possible va  [#permalink]

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28 Jan 2019, 02:05
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Difficulty:

25% (medium)

Question Stats:

71% (01:04) correct 29% (00:57) wrong based on 17 sessions

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If $$-30 ≤ 6x ≤ 60$$ and $$40 ≥ 2y + 4 ≥ 8$$, what is the greatest possible value of x − y ?

A. 23
B. 13
C. 10
D. 8
E. 6

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Re: If -30 ≤ 6x ≤ 60 and 40 ≥ 2y + 4 ≥ 8, what is the greatest possible va  [#permalink]

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28 Jan 2019, 02:14
-30 ≤ 6x ≤ 60 and 40 ≥ 2y + 4 ≥ 8
-5 ≤ x ≤ 10 and 18 ≥ y ≥ 2

Now in order to find the greatest value of x - y, "x" has to be the largest possible integer and "y" has to be the smallest possible integer.

largest value x can take is 10 and least value that y can take is 2.

x - y = 10 - 2 = 8

OPTION: D
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Re: If -30 ≤ 6x ≤ 60 and 40 ≥ 2y + 4 ≥ 8, what is the greatest possible va  [#permalink]

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28 Jan 2019, 02:15
Bunuel wrote:
If $$-30 ≤ 6x ≤ 60$$ and $$40 ≥ 2y + 4 ≥ 8$$, what is the greatest possible value of x − y ?

A. 23
B. 13
C. 10
D. 8
E. 6

$$-30 ≤ 6x ≤ 60$$

-5≤x≤10

$$40 ≥ 2y + 4 ≥ 8$$

36≥2y≥4

18≥y≥2

now we have values of both x and y. To get max value we have take max value of x and lowest value of y.

-5 ≤ x≤ 10
2 ≤y ≤18

x - y = 10 - 2 = 8.

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Re: If -30 ≤ 6x ≤ 60 and 40 ≥ 2y + 4 ≥ 8, what is the greatest possible va  [#permalink]

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28 Jan 2019, 04:37
Bunuel wrote:
If $$-30 ≤ 6x ≤ 60$$ and $$40 ≥ 2y + 4 ≥ 8$$, what is the greatest possible value of x − y ?

A. 23
B. 13
C. 10
D. 8
E. 6

-5≤x≤10
8≥y≥2

greatest value of x-y
x has to be +ve and y min
10-2 ; 8
IMO D
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Re: If -30 ≤ 6x ≤ 60 and 40 ≥ 2y + 4 ≥ 8, what is the greatest possible va   [#permalink] 28 Jan 2019, 04:37
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