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Difficulty:
Question Stats:
78% (01:29) correct 22% (01:51) wrong based on 276 sessionsCase1: If a > 0
Case2: If 7/3 < a < 0
Case3: If 7/3 > a
i.e. \(a ≤ \frac{19}{5}\) or \(a ≥ 5\)
We will have two cases  
Case 1: 3a + 7 ≥ 0 => 3a ≥ 7 => a ≥ \(\frac{7}{3}\) => 3a + 7 = 3a + 7 => 3a + 7 ≥ 2a + 12 => a ≥ 5 And our condition was a ≥ \(\frac{7}{3}\) => a ≥ 5 is a SOLUTION  Case 2: 3a + 7 < 0 => 3a < 7 => a < \(\frac{7}{3}\) ~ 2.3 => 3a + 7 = (3a + 7) => 3a  7 ≥ 2a + 12 => 5a ≤ 19 => a ≤ \(\frac{19}{5}\) (=3.8) And our condition was a < \(\frac{7}{3}\) => a ≤ \(\frac{19}{5}\) is a SOLUTION 

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