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If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0

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Joined: 02 Sep 2009
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If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0  [#permalink]

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New post 21 Apr 2017, 06:55
1
7
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A
B
C
D
E

Difficulty:

  75% (hard)

Question Stats:

51% (02:15) correct 49% (02:15) wrong based on 131 sessions

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Manager
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Posts: 59
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Re: If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0  [#permalink]

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New post 21 Apr 2017, 07:03
2
given 3x+4y<0
statement 1st: provided y> 0, x has to be negative to satisfy the question stem => sufficient
statement 2nd : 3x +5y =20 but 3x+4y <0 => y>0 => x<0 => sufficient
option-D
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Re: If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0  [#permalink]

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New post 21 Apr 2017, 07:49
1
attari92 wrote:
given 3x+4y<0
statement 1st: provided y> 0, x has to be negative to satisfy the question stem => sufficient
statement 2nd : 3x +5y =20 but 3x+4y <0 => y>0 => x<0 => sufficient
option-D


hi can u explain ur statement 2
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Re: If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0  [#permalink]

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New post 21 Apr 2017, 23:37
1
attari92 wrote:
given 3x+4y<0
statement 1st: provided y> 0, x has to be negative to satisfy the question stem => sufficient
statement 2nd : 3x +5y =20 but 3x+4y <0 => y>0 => x<0 => sufficient
option-D

IMO A

since we dont know the sign of y in statement 2 so we can say anything about answer being D
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Re: If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0  [#permalink]

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New post 22 Apr 2017, 06:15
1
1
varundixitmro2512 wrote:
attari92 wrote:
given 3x+4y<0
statement 1st: provided y> 0, x has to be negative to satisfy the question stem => sufficient
statement 2nd : 3x +5y =20 but 3x+4y <0 => y>0 => x<0 => sufficient
option-D

IMO A

since we dont know the sign of y in statement 2 so we can say anything about answer being D



look, it's been mentioned in the question stem that 3x+4y<0 but how come 3x + 4y +y =20 ? It means that the negative part (3x+4y) ought to be added with a positive 'y' in order to make the expression equals 20 , you see
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If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0  [#permalink]

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New post 10 Sep 2017, 09:32
1
A. -3x>4y - statement 1 - y>0, means -3x>a where a is 4y which is a positive value and for -3x to be greater than the positive value x shall be < 0. Hence sufficient.
Statement 2 - 3x+5y=20 which is also an equation of a decreasing line as the slope is negative and the values for the (x,y) pair can be (-10,10), (-5,7), (0,4), (5,1), (10,-2) where can be negative or less than zero but it can also be positive but for all positive values of x the equation -3x>4y will not be satisfied hence x can only be <0. Hence statement 2 is sufficient. So answer is D

sorry missed an important point there so updated the response. correct answer is D.

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If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0  [#permalink]

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New post 30 Dec 2017, 09:23
Bunuel wrote:
If -3x > 4y, is x < 0?

(1) y > 0

(2) 3x + 5y – 20 = 0


Given -3x>4y

Find is x<0 i.e is 'x'-ve

Now -3x > 4y
=> OR 3x < -4y
=> OR x < \(\frac{-4}{3}\)*y ---(1)
=> Therefore from (1) x<0 FOR SURE if y>0

Statement 1 y>0
=> Since y>0, Therefore x<0 SUFFICIENT

Statement 2 3x+5y-20=0
=> 3x+5y=20 ------------- (2)
=> Given 3x<-4y
=> OR 3x+4y<0
=> OR 3x+4y+y<0+y
=> OR 3x+5y<y
=> OR 20<y ------- from (2)
=> OR y>20
=> Since y>20 i.e y>0
=> Therefore 'x' is -ve i.e x<0
=> SUFFICIENT

Therefore 'D'

Thanks
Dinesh
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If -3x > 4y, is x < 0? (1) y > 0 (2) 3x + 5y – 20 = 0   [#permalink] 30 Dec 2017, 09:23
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